elias001
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Questions;
For the three definitions quoted in the below Background section, I would like to know what the subtle differences are. I know they all have to do with extracting diagonal sequence from a bunch of sequences and its convergence. Especially with Definition 2., why it seems to be written so much different in its property ##(b)##. I am guessing for the other two definitions, they are appear to be similar in wordings and notations, but I would like somebody who have seen these definitions or work with them explain to me their subtle differences and reasons for them.
Background
The following three definitions are taken respectively from the following books:
An Introduction to Multivariable Analysis from Vector to Manifold by: Piotr Mikusinski and Michael D. Taylor
Hilbert Spaces with Applications by Lokenath Debnath and Piotr Mikusinski
Operational Calculus, Vol 2 by: Jan Mikusinski, Thomas K. Boehme
[From Mikusinski and Taylor]
Definition 1.
Let ##(X,d)## be a metric space and let ##x_{n,k} \in X## for ##k,n \in N##. Prove that if
$$x_{1,1},x_{1,2},x_{1,3}, \ldots \rightarrow x$$
$$x_{2,1},x_{2,2},x_{2,3}, \ldots \rightarrow x$$
$$x_{3,1},x_{3,2},x_{3,3}, \ldots \rightarrow x$$
$$\vdots$$
$$x_{n,1},x_{n,2},x_{n,3}, \ldots \rightarrow x$$
$$\vdots$$
then there exists an increasing sequence of natural numbers ##p_n## such that ##x_{n,p_n} \rightarrow x.##
[From Debnath and Mikusinski]
Definition 2.
Theorem 1.4.12. (Diagonal theorem) Let ##E## be a normed space and let ##(x_{ij}), i,j\in \Bbb{N}## be an infinite matrix of elements of ##E##. If
##(a)## ##\lim_{i\to\infty}=0## for every ##j\in \Bbb{N}## and
##(b)## every increasing sequence of indices ##(p_j)## has a subsequence ##(q_j)## such that
$$\lim_{i\to\infty}\sum_{j=1}^{\infty}x_{q_iq_j}=0,$$
then ##\lim_{i\to\infty}x_{ij}=0.##
[From Mikusinski and Boehme]
Definition 3. 6. The diagonal subsequence property.
A space with a sequential convergence defined on it is said to have diagonal subsequence property if for each double sequence ##x_{n,m}, n,m=1,2,\ldots,## satisfying
$$(i)\quad\text{ for each }n\;\;\;x_{n,m}\to x_n\text{ as }m\to \infty,$$
and
$$(ii)\quad x_n\to x\text{ as }n\to \infty$$
there is a diagonal subsequence ##p_i=x_{n(i),m(i)}## where ##n(i)\to \infty, m(i)\to \infty## as ##i\to \infty,## such that
$$p_i\to x\text{ as }i\to \infty.$$
Thank you in advance.
For the three definitions quoted in the below Background section, I would like to know what the subtle differences are. I know they all have to do with extracting diagonal sequence from a bunch of sequences and its convergence. Especially with Definition 2., why it seems to be written so much different in its property ##(b)##. I am guessing for the other two definitions, they are appear to be similar in wordings and notations, but I would like somebody who have seen these definitions or work with them explain to me their subtle differences and reasons for them.
Background
The following three definitions are taken respectively from the following books:
An Introduction to Multivariable Analysis from Vector to Manifold by: Piotr Mikusinski and Michael D. Taylor
Hilbert Spaces with Applications by Lokenath Debnath and Piotr Mikusinski
Operational Calculus, Vol 2 by: Jan Mikusinski, Thomas K. Boehme
[From Mikusinski and Taylor]
Definition 1.
Let ##(X,d)## be a metric space and let ##x_{n,k} \in X## for ##k,n \in N##. Prove that if
$$x_{1,1},x_{1,2},x_{1,3}, \ldots \rightarrow x$$
$$x_{2,1},x_{2,2},x_{2,3}, \ldots \rightarrow x$$
$$x_{3,1},x_{3,2},x_{3,3}, \ldots \rightarrow x$$
$$\vdots$$
$$x_{n,1},x_{n,2},x_{n,3}, \ldots \rightarrow x$$
$$\vdots$$
then there exists an increasing sequence of natural numbers ##p_n## such that ##x_{n,p_n} \rightarrow x.##
[From Debnath and Mikusinski]
Definition 2.
Theorem 1.4.12. (Diagonal theorem) Let ##E## be a normed space and let ##(x_{ij}), i,j\in \Bbb{N}## be an infinite matrix of elements of ##E##. If
##(a)## ##\lim_{i\to\infty}=0## for every ##j\in \Bbb{N}## and
##(b)## every increasing sequence of indices ##(p_j)## has a subsequence ##(q_j)## such that
$$\lim_{i\to\infty}\sum_{j=1}^{\infty}x_{q_iq_j}=0,$$
then ##\lim_{i\to\infty}x_{ij}=0.##
[From Mikusinski and Boehme]
Definition 3. 6. The diagonal subsequence property.
A space with a sequential convergence defined on it is said to have diagonal subsequence property if for each double sequence ##x_{n,m}, n,m=1,2,\ldots,## satisfying
$$(i)\quad\text{ for each }n\;\;\;x_{n,m}\to x_n\text{ as }m\to \infty,$$
and
$$(ii)\quad x_n\to x\text{ as }n\to \infty$$
there is a diagonal subsequence ##p_i=x_{n(i),m(i)}## where ##n(i)\to \infty, m(i)\to \infty## as ##i\to \infty,## such that
$$p_i\to x\text{ as }i\to \infty.$$
Thank you in advance.
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