How Are These Resistors in Parallel

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
3 replies · 2K views
FAS1998
Messages
49
Reaction score
1
I’ve included an image of a solution to a problem from my textbook. Part of the problem is to find the equivalent resistance of the given circuit. In the solution they seem to be treating the resistors as if they were in parallel. I don’t understand why they are doing this.

For the two resistors to be in parallel would they not need to have both nodes in common? The resistors in the series don’t appear to have this property.

[Moderator's note: Moved from a technical forum and thus no template.]
 

Attachments

  • 2D28AAC6-E94D-421A-B08F-FBAD8BAD3E64.jpeg
    2D28AAC6-E94D-421A-B08F-FBAD8BAD3E64.jpeg
    20.9 KB · Views: 225
Last edited by a moderator:
Physics news on Phys.org
FAS1998 said:
I’ve included an image of a solution to a problem from my textbook. Part of the problem is to find the equivalent resistance of the given circuit. In the solution they seem to be treating the resistors as if they were in parallel. I don’t understand why they are doing this.

For the two resistors to be in parallel would they not need to have both nodes in common? The resistors in the series don’t appear to have this property.

[Moderator's note: Moved from a technical forum and thus no template.]
It might clarify matters if you post the whole question.
 
haruspex said:
It might clarify matters if you post the whole question.
Here’s the original question. It states that the circuit is a voltage divider, which I believe implies that the resistors are in series, and then the solution uses the equation for resistors in parallel to calculate the equivalent resistance.

I’ve seen similar things elsewhere in the textbook solutions so I assume I’m doing something wrong, and it’s not just a mistake in the solution.
 

Attachments

  • B80E3672-F0D8-4F65-9079-D7956C4473D8.jpeg
    B80E3672-F0D8-4F65-9079-D7956C4473D8.jpeg
    41.7 KB · Views: 214
FAS1998 said:
Here’s the original question. It states that the circuit is a voltage divider, which I believe implies that the resistors are in series, and then the solution uses the equation for resistors in parallel to calculate the equivalent resistance.

I’ve seen similar things elsewhere in the textbook solutions so I assume I’m doing something wrong, and it’s not just a mistake in the solution.
The key is the meaning of "equivalent output resistance".
See if the answer given here helps:
https://electronics.stackexchange.com/questions/265800/voltage-divider-output-resistance?rq=1