Three Resistors of magnitude R each are arranges in a circuit, as seen in the figure (added below).
Calculate the resistance of the circuit between points A and B.
If they're in parallel, I have 1/R_t = 1/R + 1/R + 1/R
If they're in series, I have R_t = R + R + R
Other potentially helpful things:
Given that they're all on the same branch, I had assumed that they were in series with one another. But with the middle resistor having being on the middle of three branches, it looks parallel.
Like I said, I have a feeling it's in series (making the answer 3R).
This question is from a past paper that I cannot get the solutions to due to policy reasons. It's worth 15 marks out of 180, so both of these answers seem too simple.
Any help is appreciated, thanks!