How can [a+,[a+,a]]=0 be proven in the quantum oscillator system?

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SUMMARY

The discussion focuses on proving the commutation relations in the quantum harmonic oscillator system, specifically demonstrating that the nested commutators [a+, [a+, a]] = 0 and [a, [a+, a]] = 0 hold true. The operators a+ and a represent the raising and lowering ladder operators, respectively. Key formulas utilized include the Jacobi Identity and the action of the operators on quantum states, which are essential for deriving these relations.

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  • Understanding of quantum mechanics, specifically the quantum harmonic oscillator model.
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Homework Statement


Actually the question is two long and I'll be done if I can show that
[a+,[a+, a]=0 and similarly
[a,[a+, a]=0
where a+ is the raising and a is the lowering ladder operator in quantum oscillator.

Homework Equations


I tried the formulas
[A,[B,C]]= -[C,[A,B]] -[B,[C,A]] and
a[tex]\psi[/tex]n=[tex]\sqrt{n}[/tex][tex]\psi[/tex]n-1
a+[tex]\psi[/tex]n=[tex]\sqrt{n+1}[/tex][tex]\psi[/tex]n+1

The Attempt at a Solution

 
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meanyack said:
I tried the formulas
[A,[B,C]]= -[C,[A,B]] -[B,[C,A]] and

The Jacobi Identity is [A,[B,C]] = [[A,B],C] + [B,[A,C]]
 
why can't I see a button "delete topic" because this is the wrong topic, the original one is the other one
 
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