How can [a+,[a+,a]]=0 be proven in the quantum oscillator system?

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Homework Statement


Actually the question is two long and I'll be done if I can show that
[a+,[a+, a]=0 and similarly
[a,[a+, a]=0
where a+ is the raising and a is the lowering ladder operator in quantum oscillator.

Homework Equations


I tried the formulas
[A,[B,C]]= -[C,[A,B]] -[B,[C,A]] and
a[tex]\psi[/tex]n=[tex]\sqrt{n}[/tex][tex]\psi[/tex]n-1
a+[tex]\psi[/tex]n=[tex]\sqrt{n+1}[/tex][tex]\psi[/tex]n+1

The Attempt at a Solution

 
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meanyack said:
I tried the formulas
[A,[B,C]]= -[C,[A,B]] -[B,[C,A]] and

The Jacobi Identity is [A,[B,C]] = [[A,B],C] + [B,[A,C]]
 
why can't I see a button "delete topic" because this is the wrong topic, the original one is the other one
 
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