How can DC-to-DC power transformers improve efficiency in power electronics?

  • Thread starter Thread starter anorlunda
  • Start date Start date
  • Tags Tags
    Power Transformer
Click For Summary
SUMMARY

DC-to-DC power transformers significantly enhance efficiency in power electronics by enabling direct connections between different voltage level HVDC lines and facilitating the integration of renewable energy sources like solar and offshore wind farms without the need for AC conversion. The core technology involves a "column" of capacitors that utilize a sorting solution for charge equalization, allowing for high-frequency switching and effective current smoothing. Simulations demonstrate the capability of these transformers to manage bidirectional power flow with minimal ripple, showcasing their potential advantages over traditional DC-AC-DC configurations.

PREREQUISITES
  • Understanding of HVDC (High Voltage Direct Current) systems
  • Familiarity with capacitor charge dynamics and switching electronics
  • Knowledge of power electronics simulation techniques
  • Basic principles of renewable energy integration into power grids
NEXT STEPS
  • Research "CIGRE papers on HVDC technology" for in-depth technical insights
  • Explore "capacitor sorting techniques" for charge equalization in power systems
  • Learn about "power loss calculations in DC-DC converters" for performance evaluation
  • Investigate "simulation tools for power electronics" to model HVDC systems
USEFUL FOR

Electrical engineers, power electronics specialists, and renewable energy developers seeking to optimize HVDC systems and improve efficiency in power transmission.

anorlunda
Staff Emeritus
Science Advisor
Homework Helper
Insights Author
Messages
11,326
Reaction score
8,754
I am sharing this to brag about my former boss and mentor Lionel Barthold. He is well into his 90s, but his mind is so sharp that he continues with brilliant inventions. I'm very proud of him.

What would power level DC-DC transformers be good for?
  • Connecting different voltage level HVDC lines without conversion to AC.
  • Direct connection of solar farms to HVDC without conversion to AC.
  • Offshore wind farms are best connected to land with underwater HVDC cables. They can generate low voltage DC and connect to HVDC without conversion to AC.
How does it work? You can read the details in this CIGRE paper, or this patent application. Or you can read my 10 cent simplified version below.

The basic element is a "column" which is a collection of a large number of capacitors in series, with a bypass switch around each capacitor. Connect the column to the high voltage side and the capacitors charge up. Now disconnect the high voltage side (all switching is done at current zeroes), bypass some of the capacitors and connect the column to the low voltage side. But that's unstable, because on the next cycle the capacitors don't begin with equal initial charges. The solution is to choose different subsets of the capacitors for each half cycle. That is called the "sorting" solution for charge equalization. None of the capacitors ever get fully discharged. With a large number of capacitors to choose from, you can do a lot of smoothing. The switching frequency is as high as possible, limited by switching speeds. Also throw in a little L to charge resonantly.

I think it is very clever. All of us could solve the simple DC circuit for each half cycle. But the circuit configuration is changed 800 times per second. If we say that each of 500 capacitors can have 4 charge levels, and switching frequency is 400 hertz, then there are ##800*2^{500}*4^{500}## possible combinations per second. But ##4^N## is an overestimate because initial charges are not fully independent, they depend on the time history. Even so, the result is a very large number of switching+initial_condition configurations per second, well above ##10^{100}##. Some of the capacitors are redundant, allowing for failures.

The scheme is shown below. One "column" on the left and with three parallel "columns" on the right. The three columns help smooth the current. (Don't get confused, this is not three phase power, it is three DC devices in parallel.)
slask.png
Here's a schematic showing details of the switching electronics.
slask.png


Here's a little simulation. We have a 640KV bus, 200 km of HVDC line, the transformer, another 200 km of line, and an 800 KV bus. The transformer has 400 submodules in each column. Switching frequency is 400 hertz.

slask.png


The simulation shows a transient, +1000 MW transfer, zero MW, then -1000 MW, in only 6 seconds. demonstrating bidirectional power flow with the same bus voltages. The transients show below are at the transformer. The currents have an enormous amount of ripple, but it is high frequency. At the bus ends of the lines, the ripples are largely filtered out by the inductance and capacitance of the 200 km of line, so that the DC looks fairly smooth.

slask.png


Just wanted to share. I think this stuff is cool.
 
Last edited:
  • Like
Likes donpacino and jim hardy
Engineering news on Phys.org
"Bucket and Ladle" charge pump taken where no man has tread before !

That's great !

thanks ..
 
  • Like
Likes mheslep
Thats really cool. I like it. just a note both of your links appear to go to the same article.

How do you think the power loses would compare vs a typical DC-AC-DC configuration.
Yes you are getting rid of the transformers but you gain the power loss that occurs with each capacitor discharge. Just curious if the simulation holds that data?

Again really cool!
 
donpacino said:
both of your links appear to go to the same article.

Thanks, i repaired the link to the patent application.

To me, calculating power losses in power electronics is very difficult, so I can't answer your question. But the losses comparison for transforming DC voltage the conventional way should not be DC-AC/AC-DC but rather DC-AC/transformer/AC-DC.
 
Most likely this can only be answered by an "old timer". I am making measurements on an uA709 op amp (metal can). I would like to calculate the frequency rolloff curves (I can measure them). I assume the compensation is via the miller effect. To do the calculations I would need to know the gain of the transistors and the effective resistance seen at the compensation terminals, not including the values I put there. Anyone know those values?

Similar threads

  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 10 ·
Replies
10
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 9 ·
Replies
9
Views
4K
Replies
1
Views
2K
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K