How can different distances and speeds result in the same velocity?

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Homework Help Overview

The discussion revolves around understanding how different distances and times can yield the same velocity. Participants are examining the calculations of velocity based on given distances and times, questioning the implications of these results.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are attempting to reconcile the calculations of velocity from different distance and time values. Questions arise about the accuracy of approximations and the interpretation of the results.

Discussion Status

There is an ongoing exploration of the concept of velocity as a ratio of distance to time. Some participants express confusion, while others assert that the calculations are straightforward, indicating a divergence in understanding.

Contextual Notes

There are indications of differing interpretations regarding the approximation of velocity values, as well as a potential misunderstanding of the relationship between distance, time, and velocity.

BUTTER-BENZ
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10m/13s = .769 m/s (made into 8m/s)

but 25m/32s = .78125 m/s (also made into 8 m/s)

how can they both be 8 m/s? when they have a different distance and speed?
 
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BUTTER-BENZ said:
10m/13s = .769 m/s (made into 8m/s)

but 25m/32s = .78125 m/s (also made into 8 m/s)

how can they both be 8 m/s? when they have a different distance and speed?

made into 8 m/s ? It should be .8 m/s, they just approximated the number


marlon
 


and they don't have different distance and SPEED !marlon
 


so .8 is a correct answer for BOTH :S
 


so confusing..
 


BUTTER-BENZ said:
so confusing..

why is this confusing ?

it's easy as hell...

velocity is the ratio of distance and time, so even if distance and time differ the ratio can be the same...
this is just like saying 2 = 10/5 or 2 = 6/3

marlon
 

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