How can Greenland lose 269b tons/year and loose only 269km3?

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IvicaPhysics
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The density of ice is 920 kg/m3.
Now let's calculate.
m = 269 000 000 000 000 kg
p = 920 kg/m3
-----------------------------
v=?
V=m/p
V=269 000 000 000 000 kg / 920 kg/m3
V = 292 391 304 347 m3 = 292 391 304.347 km3
v > 269 km3
*NOTE* I made a mistake in the title. I meant to write 269 km3
[Note: Title fixed by moderator]
 
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IvicaPhysics said:
V = 292 391 304 347 m3 = 292 391 304.347 km3
There's your problem. If 1 km = 1000 m, then 1 km3 = (1000 m)3 = 1 000 000 000 m3.
 
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It would be interesting to know the source of the original two numbers. For example was the mass calculated from the volume anyway or was the mass measured independently by gravitational survey?
 
IvicaPhysics said:
V = 292 391 304 347 m3 = 292 391 304.347 km3
v > 269 km3

As DrClaude said, 1 km3 = (1,000m)3=1,0003m3=109 m3
or
1m3 = (0.001km)3=0.0013km3=10-9km3
so
V = 292 391 304 347 m3 x 10-9km3/m3= 292. 391 km3