How can I find an objects # of revolutions as it accelerates

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Homework Help Overview

The discussion revolves around a problem involving angular acceleration of a crankshaft in a race car, specifically how to determine the number of revolutions made while accelerating from rest to a specified speed. The subject area includes concepts of rotational motion and angular kinematics.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • The original poster attempts to calculate angular acceleration and seeks guidance on how to find the number of revolutions during acceleration. Some participants question the accuracy of the calculated angular acceleration and suggest comparing angular motion to linear motion for clarity.

Discussion Status

Participants are exploring different interpretations of the problem, particularly regarding the calculation of angular acceleration and its implications for the number of revolutions. Some guidance has been offered regarding the relationship between angular distance and time, but no consensus has been reached on the calculations.

Contextual Notes

There is a noted concern about the use of proper formatting in the homework area, and some participants are questioning the assumptions made in the calculations, particularly regarding units and the interpretation of angular acceleration.

Kacie
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The crankshaft in a race car goes from rest to 3180rpm in 2.4s .

a) What is the crankshaft's angular acceleration? >>Which I found to be ~140rad/s^2

b) How many revolutions does it make while reaching 3180rpm ?

How can I find the answer to b) ? I'm not even sure where to start..
 
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Hi Kacie,

Welcome to Physics Forums.

In future please be sure to use the formatting template provided in the editing window whn you post a question here in the homework areas. It's in the forum rules.

For part b, you have an angular acceleration and a time. How many radians (angular distance) will the shaft rotate during that time?

It may be helpful to compare this to a linear analogy where you have acceleration and time. What formula would you use to find the distance that an object moves if it starts from rest and accelerates at a constant rate a for time t?
 
? For (a), if you accelerate at 140 revs per second per second for 2.4 seconds, you will go from 0 to 140(2.4)= 336 revs per second. 336(60)= 20160 revs per minute, not 3180. How did you get 140?

Assuming that increase is at constant "acceleration", then we can take an average revs per minute as the average of the initial and end values: (0+ 3180)/2= 1590 revs per minute. How many revolutions would it make at 1590 revs per minute in 2.4 s?
 
HallsofIvy said:
? For (a), if you accelerate at 140 revs per second per second for 2.4 seconds, you will go from 0 to 140(2.4)= 336 revs per second. 336(60)= 20160 revs per minute, not 3180. How did you get 140?
Kacie's acceleration result had units of radians per second per second, not rotations/s/s.
 

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