How can I find the eigenvectors and basis for the eigenspace of a given matrix?

  • Thread starter Thread starter jjones1573
  • Start date Start date
  • Tags Tags
    Eigenvectors
Click For Summary

Homework Help Overview

The discussion revolves around finding the eigenvectors and basis for the eigenspace of a given 2x2 matrix. The matrix in question is A = [6, 16; -1, -4], with eigenvalues λ = 4 and λ = -2 being considered.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • The original poster attempts to apply the eigenvalue equation (A - λI)v = 0 to find eigenvectors for the specified eigenvalues. They express uncertainty regarding the correctness of their derived basis for the eigenspace and seek clarification on the definition of eigenvectors.

Discussion Status

Participants are actively engaging with the original poster's attempts, providing corrections and affirmations regarding the calculations. There is a discussion about the necessity of normalizing the eigenvectors and the implications of different representations of the same vector.

Contextual Notes

There is a mention of a potential misplacement of the thread in the forum, indicating that the topic may be more suited for a different section. The original poster also expresses confusion about the concept of eigenvectors, suggesting a need for further clarification.

jjones1573
Messages
22
Reaction score
0

Homework Statement


Im looking at finding the eigenvectors of a matrix but also a basis for the eigenspace

A = [ 6 16 ]
[ -1 -4 ]

lambda = 4
lambda = -2


Homework Equations


(A - lambda I ) v = 0


The Attempt at a Solution



So with the above equation I get:

for lambda = 4

[ 6 - 4 16 ] [ v1 ] = [ 0 ]
[ -1 -4 - 4 ] [ v2 ] [ 0 ]

so

2 v1 + 16 v2 = 0
-v1 - 8v2 = 0

so v1 = 8v2

and the basis for the eigenspace is span [ 8 ]
[ 1 ]

First is that right? because when I put it into an eigenvector calculator on the web it gives me
-8 instead of 8 but I can't see how I could get to that.

Second if this is the basis for the eigenspace then how can I find the eigenvectors for the eigenvalue?

thanks,
 
Physics news on Phys.org
jjones1573 said:
2 v1 + 16 v2 = 0
-v1 - 8v2 = 0

so v1 = 8v2

You made a sign error. v1=-8v2

ehild
 
Oh yeah that's right thanks.

Is it as simple as the vector is:

[-8v2]
[v2]

and the eigenspace is: span

[-8]
[1]
 
Sorry I realized this should have been posted in the calculus section would it be possible to have it moved?

I think what I have put above for the eigenspace is correct? But what about the eigenvector I can't seem to understand what this is.
 
(-8,1) multiplied by any number is an eigenvector. You need to find the other one, which belongs to the other eigenvalue lambda=2.
The two eigenvectors are the basis of the "eigenspace". You can choose the normalised vectors as basis.

ehild
 
Oh thanks. Do I need to normalise the vectors or is it fine to just find the two vectors and give that?
 
You do not need to normalize in principle.

ehild
 
ok thanks.
 

Similar threads

Replies
2
Views
2K
Replies
40
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 33 ·
2
Replies
33
Views
3K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 13 ·
Replies
13
Views
3K
Replies
5
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 18 ·
Replies
18
Views
4K