How can I make a manual hydraulic log splitter using a lever?

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SUMMARY

This discussion focuses on constructing a manual hydraulic log splitter utilizing lever mechanics. Key principles include the application of Pascal's law, which states that pressure is equal to force divided by area. For instance, using a 1-inch diameter piston to exert force on a 3-inch diameter piston can amplify the force significantly, as demonstrated by calculations showing a 10 lbs force on the smaller piston resulting in 90 lbs on the larger piston. Participants express a need for comprehensive tutorials on hydraulic systems and components, including hydraulic rams and pumps.

PREREQUISITES
  • Understanding of Pascal's law in hydraulics
  • Basic knowledge of force and pressure calculations
  • Familiarity with hydraulic components such as pistons and pumps
  • Experience with mechanical lever systems
NEXT STEPS
  • Research hydraulic ram design and functionality
  • Study hydraulic pump operation and selection
  • Explore flow diverters and their applications in hydraulic systems
  • Learn about mechanical lever systems and their advantages in force multiplication
USEFUL FOR

This discussion is beneficial for DIY enthusiasts, mechanical engineers, and anyone interested in building or understanding manual hydraulic systems for log splitting.

anonymoussome
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We are thinking of making a project on Hydraulic manual log splitter.

But the problem is we don't know much about hydraulic principles and stuff...
could somebody provide me with the link of complete tutorial for manual hydraulic machines.

We wish to make it hand or foot operated using lever...but how to do that we have many doubts.

Help!
 
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I hope you are tying to split small logs. My purchased log splitter uses upwards of 20 tons of force to split logs.

Anyways, you can just look at simple force vs area calculations.

For example,

Pressure = force/area

Say you have a 3 inch diameter piston and you are planning to move a 3 inch diameter piston by providing force on the 1 inch diameter piston.

The area of the 1 inch piston is simply (1^2*(3.141592))/4 = 0.7854 square inches.

In a similar fashion the 3 inch piston is 7.0686 square inches.

Now with a force on the 1 inch piston of 10 lbs will create a pressure of 12.73 psi.

Using a simple ratio of pressure on the 1 inch piston to the 3 inch piston the resulting force on the 3 inch pistion is 90 lbs. That is 9 times higher then the initial force of 10 lbs on the 1 inch piston.

Another example, is a car jack. You provide a small force on the small piston and the larger piston provides a large force that easily lifts the car upwards.

Hope that helps.

Thanks
Matt
 
I know the Pascal law...I want to know how hydraulics work and how to change the direction of motion

Like I am pulling the lever and the piston is moving forward. How to realize that?
 
So you are looking for information on the hydaulic ram, pump, flow diverter flow, and other log splitter components?

Thanks
Matt
 
yes sir I am looking for this info.
 

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