I get 18586- with decimal part .o345...
To solve for [itex]\theta[/itex], "unpeel" what has been done:
[tex]d= \frac{v^2sin(2\theta)}{g}[/tex]
so, multiplying both sides by g,
[tex]dg= v^2 sin(2\theta)[/itex]<br />
dividing both sides by [itex]v^2[/itex],<br />
[tex]\frac{dg}{v^2}= sin(2\theta)[/tex]<br />
Taking the inverse sine (arcsin) of both sides<br />
(be careful- since sine is not one-to-one there is no "true" inverse- there are an infinite number of angles with the same sine- two between 0 and pi/2- and "arcsin" only gives one of them)<br />
[tex]arcsin\left(\frac{dg}{v^2}\right)= 2\theta[/tex]<br />
and, finally, divide both sides by 2:<br />
[tex]\frac{1}{2}arcsin\left(\frac{dg}{v^2}\right)= \theta[/tex][/tex]