How can I simplify this complex expression?

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Homework Help Overview

The discussion revolves around simplifying a complex mathematical expression involving radicals and algebraic terms, specifically in the context of solving an equation for the variable x.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss various attempts to simplify the expression and clarify the equation's structure. Some express uncertainty about how to handle the radical terms and the overall simplification process.

Discussion Status

There are multiple interpretations of the expression being simplified, with participants offering different algebraic manipulations and suggestions for rewriting the equation. Some guidance has been provided regarding squaring terms and rearranging the equation, but no consensus has been reached on a definitive simplification method.

Contextual Notes

Participants are working under the constraints of homework rules, focusing on simplification before solving for x. There is an acknowledgment of the complexity of the expression and the challenges posed by the radical components.

white1995gt
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I need the following expression simplified.

36/[64.4*(0.5+(2+ x)*((1-(1/4)*x^2 )^0.5)) ]-x*((1-(1/4)*x^2 )^0.5)=0
 
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What have you tried?

Also, this is an equation, so the likely thing to do would be to solve it for x.
 
I just need to simplify first then I have to solve for x. I got the following once I factored everything out and simplified things:

(259*x^8)+(1037*x^7)-(1037*x^6)-(8294*x^5)-(4406*x^4)+(16589*x^3)+(17626*x^2)
 
Actually I think I'm wrong. I think I could get it if someone could square the following expression for me:

64.64 * [0.5 + (2 + x) * (Sqrt[1 - (0.25*x^2)])]

I just can't get it no matter what I try.
 
white1995gt said:
I need the following expression simplified.

36/[64.4*(0.5+(2+ x)*((1-(1/4)*x^2 )^0.5)) ]-x*((1-(1/4)*x^2 )^0.5)=0
Is this the equation?
[tex]\frac{36}{64.4(1/2 + (2 + x)\sqrt{1 - x^2/4})} - \frac{x}{\sqrt{1 - x^2/4}} = 0[/tex]

If so, you can write it as
[tex]\frac{36}{64.4(1/2 + (2 + x)\sqrt{1 - x^2/4})} = \frac{x}{\sqrt{1 - x^2/4}}[/tex]

You can square both sides. I would move the 64.4 up into the numerator so that the new first numerator is 36/64.4 and the denominator of the expression on the left is
[tex](1/2 + (2 + x)\sqrt{1 - x^2/4})[/tex]

The square of this expression is (1/2)^2 + 2(1/2)(2 + x)sqrt(1 + x^2/4) + (2 + x)^2 * (1 - x^2/4). Everything else is pretty straightforward.
 
Last edited:
It's actually this:

[tex] \frac{36}{64.4(1/2 + (2 + x)\sqrt{1 - x^2/4}} ) - {x}{\sqrt{1 - x^2/4}} = 0[/tex]
 
Rewrite as [tex] \frac{36/64.4}{1/2 + (2 + x)\sqrt{1 - x^2/4}} = {x}{\sqrt{1 - x^2/4}}[/tex]

and multiply both sides by sqrt(1 - x^2/4).
 
I'm not really sure how to simplify the radical because it's inside the parenthesis. I doubt it's as simple as this:

[tex] <br /> \frac{36/64.4} {1/2 + (2 + x)} = {x}(1 - x^2/4)[/tex]

Sorry that the parenthesis aren't closed I'm still trying to get used to posting here.
 
Mark44 said:
Rewrite as [tex] \frac{36/64.4}{1/2 + (2 + x)\sqrt{1 - x^2/4}} = {x}{\sqrt{1 - x^2/4}}[/tex]

and multiply both sides by sqrt(1 - x^2/4).

On second thought, I think it makes more sense to multiply both sides by what's in the denominator on the left side.
 
  • #10
Thank you for all the help. I got mathematica the other day and just got the answer after playing around with it a little bit.
 

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