How can I simplify this expression without using a calculator?

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Homework Help Overview

The original poster presents an expression involving sine, specifically sin(theta) = [√3 + 1 - √(4 - 2√3)]/4, and seeks to simplify it without the aid of a calculator. The context revolves around trigonometric simplification and algebraic manipulation.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss rewriting the term 4 - 2√3 as a square, questioning the appropriate form and values involved. There are also considerations about the order of operations in mathematical expressions.

Discussion Status

Some participants have offered guidance on how to approach the simplification, while others have raised questions about the assumptions made in the original expressions. The discussion appears to be ongoing with various interpretations being explored.

Contextual Notes

There is a mention of potential confusion regarding the order of operations and the interpretation of square roots in the context of the problem. Additionally, the original poster's reliance on a calculator for verification is noted.

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Homework Statement


I got this expression while solving a problem.

sin(theta)=[√3+1-√(4-2√3)]/4
Using calculator I got RHS=0.5
How do we simplify it without using a calc?


Homework Equations





The Attempt at a Solution

 
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Try to write 4-2√3 as the square of (√3-a) . What is a?

ehild
 
ehild, did you intend that to be [itex]\sqrt{(3- a)}[/itex] or [itex](\sqrt{3})- a[/itex]?
 
Naturally, √3 +a = 1.7320508.. +a. You have to perform a higher operation first, and square root is of higher order than addition or subtraction. So is multiplication to addition. 2*3+4 =10 and it is not the same as 2*(3+4)=14. Or 6/2+3=6, and not 6/(2+3)=1.2. √9+16=19 and it is not √(9+16)=5. The square of (√3-1) is (√3-1)^2 = 4-2√3 and not √3-1^2=√3-1. Or it is on the other way at other parts of the world?

ehild
 
ehild said:
Naturally, √3 +a = 1.7320508.. +a. You have to perform a higher operation first, and square root is of higher order than addition or subtraction. So is multiplication to addition. 2*3+4 =10 and it is not the same as 2*(3+4)=14. Or 6/2+3=6, and not 6/(2+3)=1.2. √9+16=19 and it is not √(9+16)=5. The square of (√3-1) is (√3-1)^2 = 4-2√3 and not √3-1^2=√3-1. Or it is on the other way at other parts of the world?

ehild

Yes?

Abdul Quadeer, [tex]a+b=\sqrt{(a+b)^2}[/tex], see if you can work some magic with this idea.
 
Thanks, I got the answer.
Mentallic- there is a slight error in your idea.
LHS =|a+b|
 
Haha yep :smile: I didn't want to complicate things by saying in the case that a+b>0 or anything like that. You know, the KISS principle. But I'm glad you were able to spot my simplification (in other words, the error, but I'm not willing to admit it :wink:)
 
:smile:
 

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