How can I solve a trigonometric equation using algebra?

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SUMMARY

The discussion focuses on solving the trigonometric equation sin(2x) = sin(0.5x) for the interval 0 to 270 degrees using algebraic methods. Participants suggest utilizing the double angle identity, sin(2x) = 2sin(x)cos(x), to simplify the equation. Additionally, they discuss the representation of sea water depth using the function y = a + bcos((2π/k)t), identifying constants a, b, and k based on maximum and minimum depths. The conversation emphasizes the importance of understanding trigonometric identities and harmonic functions in solving such equations.

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  • Understanding of trigonometric identities, specifically double angle and half angle identities.
  • Familiarity with the concept of simple harmonic motion and its mathematical representation.
  • Basic knowledge of algebraic manipulation of trigonometric functions.
  • Ability to interpret periodic functions and their parameters.
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  • Study the derivation and application of the double angle identity for sine functions.
  • Learn how to apply the half angle identities in solving trigonometric equations.
  • Explore the properties of simple harmonic motion and its mathematical models.
  • Investigate the relationship between the period of a function and its parameters in trigonometric equations.
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Students and educators in mathematics, particularly those focusing on trigonometry and algebra, as well as anyone interested in understanding the application of trigonometric identities in real-world scenarios.

Peter G.
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Hi,

I was asked to solve for this:

sin (2x) = sin (0.5x)

For 0 to 270 degrees

I know how to solve it by plotting the two graphs, is there any other way of doing it, like, for example, algebraically?

Thanks,
Peter G.
 
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You could use the half angle and double angle identities for sin to expand both sides into something that you can work with.

For instance, on your left side:
sin(2x) is the same as sin(x+x) right?
So sin (x+x) = sinxcosx + sinxcosx, or 2sinxcosx

and you know how to solve a basic trig equation like that right?
 
I know the double angle rules but not the half angles, so I think I should've graphed them really. But I am having problems with two questions... I have only a vague idea on how to start: This is one of them:

The depth y meters of sea water in a bay at time t hours after midnight may be represented by the function:

y = a + bcos ((2π / k)t) where a and b are constants.

The water is at a maximum depth of 14.3 m at midnight and noon and is at a minimum depth of 10.3 m at 06:00 and at 18:00.

Write down the values of a, b and k:

I know a will shift the whole of the graph up or down, b will stretch it parallel to the y-axis and I think k will influence the period of the curve.

From then on however, I don't know what to do...
 
For the first question, it is really sin\theta = sin\alpha \mbox{ The solution to these type of equations is } \theta = n180 + (-1)^n\alpha \mbox{ where n is an integer }. I hope this helps
 
Well, since this is just the model of a simple harmonic, you can assume that the max at midnight and the min at 6 (and 18) are the max and mins, from that you should be able to get the amplitude of the function (b) and the constant a that shifts the graph up.

Inside the trig function you have ((2pi/k)t+0), let's call (2pi/k) B, and 0 C. 2pi over your "B" value must equal the period of the function, this can be used to determine the period of one wave if you pick a unit for time (hours perhaps). 2pi/2pi/k is really just k right? -C/B can be used to determine where your wave starts in relation to x=0.
 

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