How can I use calculus to graph f(x)= 10(ln(ln(x))/ln(x))?

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To graph the function f(x) = 10(ln(ln(x))/ln(x)), it's essential to identify key features such as vertical asymptotes and local extrema. The vertical asymptote occurs at x = 1, with an x-intercept at approximately 2.71828. To find local maxima, calculate the derivative f'(x) and determine where it equals zero, as well as analyze the sign of the derivative to ascertain intervals of increase and decrease. Additionally, the second derivative can be used to evaluate concavity. Understanding these calculus concepts simplifies the graphing process significantly.
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1. Graphing Carefully: Sketch f(x)= 10(ln(ln(x))/ln(x) accurately using calculus, your calculator, or both to aid you. Make sure to include all vertical asymptotes, as well as local extrema



2. f(x)= 10(ln(ln(x))/ln(x)



3. OK. I might come across as stupid but here goes... I don't know what to do. I looked at the graph and figured 'what is there to show?' besides a VA. So I came up with VA=1, x-intercept=2.71828, and the local max is (15.1543, 3.67879. But how do I get this with calculus? I solved for f'(x) but I do not know how to work this stuff to find/prove the max and increasing/decreasing, concavity,etc. HELP, please. Thank you.
 
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You can do all of this without a graphing calculator. For the vertical asymptote, where is the denominator zero? For x-intercepts, where is the numerator zero? For max value/min value, where is the derivative of the function zero? For where the function is increasing/decreasing, where is the derivative positive/negative? For where the function is concave up/concave down, where is the 2nd derivative positive/negative?
 
Thanks for the reply Mark44.

I worked it out! I think I made it harder that it was... a lot harder than it was.

Thanks for your help.
 
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Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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