How Can Temperature Affect the Breakdown Voltage of a Semiconductor Diode?

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Homework Help Overview

The discussion revolves around an experimental setup to investigate how temperature affects the breakdown voltage of a semiconductor diode. The original poster seeks to understand how to vary the temperature of the diode from -70 degrees C to 150 degrees C and is concerned about the safety of using hot water for heating. Additionally, they are looking for ways to calculate the breakdown voltage while avoiding damage to the diode due to large currents.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss methods for achieving the desired temperature range, including the use of dry ice and liquid nitrogen. There are questions about the safety of heating methods and how to set up the circuit to measure breakdown voltage while limiting current to protect the diode.

Discussion Status

Some participants have provided suggestions for temperature control and circuit setup, including the use of a current limiting resistor. There is ongoing clarification regarding the measurement of voltage drop across the resistor during the breakdown test, indicating that the discussion is active and participants are engaging with each other's ideas.

Contextual Notes

The original poster is working within specific constraints regarding temperature ranges and safety considerations for the diode during the experiment. There is a focus on ensuring that the diode is not damaged during the breakdown voltage testing.

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The problem is an experiment has to be set up to investigate how the breakdown voltage (which occurs by a large reverse potential difference is applied to the diode, and the diode then passes a large current) of a semiconductor diode is affected by temperature.


My problem is how can I vary the temp. of the diode in the range of minus 70 degrees C to 150 degrees C, whihc is what the question asks for,

I think I can get a range of about -10 celsius to 70 degrees , but I also want to ask whether it is safe to submerge the diode in hot water (which will be heated by a bunsen burner)?

Also how can I set up a circuit so that the breakdown Voltage is calculated BUT also avoid large currents (which would cause damage to the diode when breakdown occurs) <- this is probably the most important bit.
#


THANKS to anyone with any ideas and suggestions!
 
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Dry ice can attain approx (-60 degC). Liquid nitrogen can attain approx (-200 degC). A standard kitchen oven can be preheated (and then the heat turned off) to almost any temperature up to (+200 degC).

For the diode "reverse-bias" voltage breakdown test, place the diode in series with a current limiting resistor "R". During the test, monitor the voltage drop across R. Before breakdown, very little voltage will drop across "R" (diode limits current). After breakdown, you will see a noticeable change, and R will limit the current thru the diode.


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Last edited:
Thanks very much for your help.
 
"During the test, monitor the voltage drop across R."

by voltage drop, do you mean the voltage across R gets more negative, as the breakdown voltage is approached?
 
The voltage drop magnitude across R will increase when breakdown occurs since more current will flow through R. Whether you measure it positive or negative depends on how you've connected your meter. Presumably you'll connect your meter with the (+) lead on the terminal of R closest to the (+) voltage source. In that case, the reading will change from near 0 before breakdown to a larger (+) reading after breakdown.
 

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