How Can the Logit Function Be Modified for a Specific Output Range?

[adan]

Hi,
I am looking for changing the logit f(z) = 1/(1+exp(-z)), where z range is [-inf,+inf]. I want to adapt it as follows:
if z > 0.5 then f > 0.5
z < 0.5 then f < 0.5

Thanks

 

[BvU]

Hi,
If I understand you well, you want to shift the graph to the right by 0.5. So replace $z$ by $z-0.5$

$\$

 

[adan]

Hi,
If I understand you well, you want to shift the graph to the right by 0.5. So replace $z$ by $z-0.5$

View attachment 284871$\$

Thank you so much!

 

[Mark44]

I am looking for changing the logit f(z) = 1/(1+exp(-z))

Do you mean logistic function? That is apparently how @BvU interpreted this. I don't believe there is such a thing as a "logit" function.

 

[BvU]

https://en.wikipedia.org/wiki/Logit

 

[Mark44]

https://en.wikipedia.org/wiki/Logit

New one on me...

 

[BvU]

Me too...

Never too old to learn

$\$

 

[BvU]

Actually, the $f$ in this thread is the sigmoid function. Vaguely remember it's used in neural networks and fuzzy control.

$\$

 

[WWGD]

Hi,
I am looking for changing the logit f(z) = 1/(1+exp(-z)), where z range is [-inf,+inf]. I want to adapt it as follows:
if z > 0.5 then f > 0.5
z < 0.5 then f < 0.5

Thanks

Just a technicality : Why are you using #[\-infty, \infty]#, i.e., are you considering #\pm \infty # as actual inputs?