How can the LRS model for leptons incorporate the Standard Model group?

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SUMMARY

The discussion centers on incorporating the Standard Model (SM) group into the Left Right Symmetric (LRS) model for leptons, specifically the gauge group GLR = SU(2)L×SU(2)R×U(1)X. The key conclusion is that the SM generator Y can be expressed as Y = T3R + X/2, where T3R is one of the LRS generators. Participants emphasize the importance of understanding the relationship between the LRS and SM groups, particularly how U(1)Y is embedded within the LRS framework.

PREREQUISITES
  • Understanding of the Left Right Symmetric (LRS) model for leptons
  • Familiarity with gauge groups, specifically GLR = SU(2)L×SU(2)R×U(1)X
  • Knowledge of the Standard Model group SU(2)L×U(1)Y
  • Basic understanding of linear combinations of generators in group theory
NEXT STEPS
  • Research the implications of the LRS model on particle physics
  • Study the relationship between SU(2)R and U(1)X in the context of the LRS model
  • Explore the concept of embedding U(1)Y within larger gauge groups
  • Examine the role of the electroweak theory in connecting LRS and Standard Model frameworks
USEFUL FOR

This discussion is beneficial for particle physicists, students studying advanced theoretical physics, and researchers interested in gauge theories and their implications for the Standard Model and beyond.

Shen712
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This is a homework problem in a course in particle physics at Cornell University.
Assume the Left Right Symmetric (LRS) model for leptons. The gauge group is GLR = SU(2)L×SU(2)R×U(1)X. The Standard Model group SU(2)L×U(1)Y has to be included in the LRS group. Namely, U(1)Y ⊂ SU(2)R×U(1)X. Find the linear combination of the LRS generators which gives the Standard Model generator Y.
The answer is: Y = T3R + X/2
How to get this result?
 
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To give away the answer directly would violate Physics Forums rules. What are your own thoughts and what have you been able to conclude so far?
 
Orodruin said:
To give away the answer directly would violate Physics Forums rules. What are your own thoughts and what have you been able to conclude so far?

My thoughts are: Since the SM generator Y is proportional to identity, the required linear combination of the LRS generators must also be proportional to identity. Considering that the generators of SU(2)R are TaR = τa/2, where τa are the Pauli matrices, only the combination of T3R and X is possible to be proportional to identity. Thus, Y = T3R + kX, where k is some constant. Since TaR = τa/2, if we take k = 1/2, we will get Y = τa/2 + X/2 = diag(1+X, -1+X)/2. This is a diagonalized matrix, but not proportional to identity. I am a little puzzled.
By the way, I am not a student at Cornell University, and this course is an old one in 2008. I just downloaded the course materials from the website and study them by myself. In this case, do the Physics Forum rules allow to give away the answer?
 
Shen712 said:
In this case, do the Physics Forum rules allow to give away the answer?
No. We believe that regardless of whether you're doing an exercise as part of a course for credit, or for independent self-study, you're best served by figuring out the answer for yourself, with some help from hints and/or corrections as appropriate.
 
I suppose that since you are looking at models beyond the standard model, you have already looked at the standard model itself... haven't you?
If yes, the problem is pretty much the same as the EM charge in the Electroweak theory: SU_L(2) \times U_Y(1) \rightarrow U_{Q}(1).
 
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