Undergrad How can we prove the kinetic energy equation

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The discussion focuses on proving the kinetic energy equation through the work-energy principle, stating that the work done equals the change in kinetic energy in a mechanical system. It outlines the mathematical derivation of work done, starting from the force applied to displacement and integrating over velocity. The conversation highlights that when velocity and its differential are aligned, the standard kinetic energy equation of 1/2mv^2 holds true. It also addresses scenarios where velocity components are in different directions, suggesting that the general kinetic energy equation can still be validated by analyzing each component separately. The conclusion emphasizes the importance of considering directional components in kinetic energy calculations.
murshiddreamengineer
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does the kinetic energy equation always work? it has proved for only when acceleration and and velocity are in the same direction.
Proof of kinetic energy
work done equals a change in kinetic energy in a mechanical system.
δW = F.ds
W = ∫F.ds
W = m∫a.ds
W = m∫(dv/dt).ds
W = m∫v.dv

here if v and dv are in the same direction the change in kinetic energy will be the usual equation. what happens if both are in different directions how can we prove that the general equation for kinetic energy will be 1/2mv^2?
 
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It works individually on each component’s contribution. That is ##\int v_1 dv_1 = v_1^2/2## etc.
 
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Thank you. I forgot to think that.
 
I built a device designed to brake angular velocity which seems to work based on below, i used a flexible shaft that could bow up and down so i could visually see what was happening for the prototypes. If you spin two wheels in opposite directions each with a magnitude of angular momentum L on a rigid shaft (equal magnitude opposite directions), then rotate the shaft at 90 degrees to the momentum vectors at constant angular velocity omega, then the resulting torques oppose each other...

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