- #1
albertrichardf
- 165
- 11
Hi all,
Here is the derivation of kinetic energy from Work:
W = ∫Fds
From the second law of motion F = dp/dt, which is equal to mdv/dt, so:
W = m∫dvdx/dt which = m∫dv x v because dx/dt = v
Therefore W = 1/2mv2, when integrated.
However from simple algebra derivation, W = Δ1/2mv2.
Did I skip something in the derivation? I know that the actual integration would be 1/2mv2
+ C, where C is a constant. However I omitted the C. Is it because of that that I did not end up with the proper equation? If so, why would C = -1/2vi2. (vi because Δv = v - vi and the rest comes from kinetic energy equation.) Or is it because I wrongly integrated?
Any answers would be appreciated. Thanks
Here is the derivation of kinetic energy from Work:
W = ∫Fds
From the second law of motion F = dp/dt, which is equal to mdv/dt, so:
W = m∫dvdx/dt which = m∫dv x v because dx/dt = v
Therefore W = 1/2mv2, when integrated.
However from simple algebra derivation, W = Δ1/2mv2.
Did I skip something in the derivation? I know that the actual integration would be 1/2mv2
+ C, where C is a constant. However I omitted the C. Is it because of that that I did not end up with the proper equation? If so, why would C = -1/2vi2. (vi because Δv = v - vi and the rest comes from kinetic energy equation.) Or is it because I wrongly integrated?
Any answers would be appreciated. Thanks