How Can You Calculate the Order of Maxima in a Diffraction Grating Experiment?

Click For Summary
To calculate the order of maxima in a diffraction grating experiment, two light sources with known wavelengths are used, along with a grating and a screen at a specific distance. The equations sin(Q) = mw1/d and sin(D) = mw2/d relate the angles of diffraction to the wavelengths and slit spacing. The challenge lies in determining the distances y1 and y2 from the origin to the respective maxima, as only the distance between the maxima is provided. The relationship between the angles and distances can be utilized, but without y1 and y2, finding the order of maxima becomes difficult. Clarifying the relationship between the known distance between maxima and the distances from the origin is essential for solving the problem.
dekoi
Two light sources of known wavelengths (w1, w2) are displayed through a grating. The screen is a known distance apart, and the spacing between slits is also known. The final given piece of information is the distance between a maxima of the first wavelength and a maxima of the second wavelength. Find the value of m (m being the coefficient/scalar of the wavelength(s) to create constructive interference).

I realize that sin(Q) = mw1 / d and that tan(Q) = y1 / L, where y1 is the distance of the maxima from origin.

Similarly, sin(D) = mw2 / d and tan(D) = y2/L.

However
, I can't figure out a way to determine y1 and y2! The distance between distinct maximas is known, but the distance of one maxima to the origin and the second maxima to the origin is hard to find out!

Thank you.
 
Physics news on Phys.org
anyone?/.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 3 ·
Replies
3
Views
965
Replies
6
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
5K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 1 ·
Replies
1
Views
8K