How Can You Calculate the Probability of Rolling a Sum of 14 with 7 Dice?

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SUMMARY

The probability of rolling a sum of 14 with 7 dice can be calculated using combinatorial methods. The formula presented, 6-7[(13 choose 7)-49], indicates that the denominator represents the total outcomes of rolling 7 dice, which is 6^7. The numerator must account for the specific combinations that yield a sum of 14. To simplify the problem, it is suggested to first analyze smaller cases, such as rolling 3 dice to achieve a total of 6, which helps in understanding the counting strategy needed for the original problem.

PREREQUISITES
  • Understanding of basic probability concepts
  • Familiarity with combinatorial mathematics, specifically "n choose k" notation
  • Knowledge of probability generating functions
  • Experience with rolling dice and calculating outcomes
NEXT STEPS
  • Study the concept of probability generating functions in detail
  • Learn how to apply combinatorial counting techniques to dice problems
  • Explore the concept of "n choose k" and its applications in probability
  • Practice calculating probabilities for different sums with varying numbers of dice
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Students studying probability, mathematicians interested in combinatorial problems, and educators looking for examples of probability calculations involving dice.

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Homework Statement



Roll 7 dice. What is the probability that the sum of the numbers is 14?


Homework Equations



Possibly a probability generating function because the problem comes from the chapter that deals with it but I can't think of which one (if any actually apply).


The Attempt at a Solution



Here is the solution: 6-7[(13 choose 7)-49]

I really have no idea why. The 67 in the denominator I understand because that is the total number of different ways you can roll 7 dice. Where does the rest come from?
 
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By the definition of probability, the numerator should be the number of different ways you can roll seven dice and get a sum of 14. So how would you count them to get this answer?
 
You might start with a simpler problem to get your head around the harder problem. For example, what's the probability of rolling three dice and getting a total of 6?

The only combinations that produce a total of 6 are (2, 2, 2) and (1, 2, 3). There is only one way to get (2, 2, 2), namely that all three dice have to be 3s, but there are 6 ways to get (1, 2, 3). I've written this as an ordered triple, but I really don't mean it that way--only that one die is a one, another is a two, and the last is a three.

So for this easier problem, what's the probability that three dice will show a total of 6? Can you extend this idea to your problem?



Can you extend this counting strategy to
 

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