Probabilistic Analysis of Drawing Cards and Dice Rolls for Success Conditions

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SUMMARY

The discussion focuses on calculating the probabilities of achieving specific outcomes when drawing cards from a standard 52-card deck and rolling 30 six-sided dice. It concludes that drawing 17 cards guarantees a flush, while rolling 16 dice ensures either six different values or four of the same value. Participants emphasize the importance of defining success conditions and suggest breaking down the problem into manageable parts to analyze probabilities effectively. An experimental approach is recommended to gain practical insights into the odds involved.

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  • Understanding of basic probability concepts
  • Familiarity with combinatorial mathematics
  • Knowledge of card games and dice mechanics
  • Ability to analyze independent events in probability
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  • Study combinatorial probability in card games
  • Learn about independent events in probability theory
  • Explore simulations for dice rolls and card draws
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Mathematicians, game designers, statisticians, and anyone interested in probability theory and its applications in games of chance.

rmiller70015
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I am looking for a way to think about this type of problem and this is not a coursework problem

1. Homework Statement

How many cards from a 52 card deck of ordinary playing cards would you have to draw to have either a flush or 4 of a kind

If you have a 30 6 sided dice, how many dice rolls would it take to guarantee that there are either 6 different values or 4 of the same dice

Homework Equations

The Attempt at a Solution

 
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The first one looks like it can be solved by seeing how many 3 of a kinds you can make (without making 4 of a kind), and also how many cards you can put out with 4 in the same suit without having 5 in the same suit... It looks like you can draw 16 without getting a flush and card #17 must make a (5 card) flush. That should be quite easy to do and the 4 of a kind will not be a factor. Scratch the first part of the first sentence=it appears irrelevant. ## \\ ## For the second one, you can get 5 faces 3 times. On roll #16, you either get side 6 or 4 of the same face.
 
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1st define what you mean by "guarantee".
You want a probability of 1?

You also want to be more careful about how you are specifying the conditions for a success.
You only want to know a way of thinking about the problem ... how are you currently thinking about the problem?
You want to divide the success condition into parts, and work the probability for each part separately.
Do you understand how to combine probabilities?

It is usually easier to calculate the probability that a condition does not occur.
ie. to get all six numbers appearing on N>6 dice is the same is there not being at a number absent.
So what is the probability of there being at least one number completely absent?
Is it possible for there to be 2 numbers completely absent?

With the cards you can get to p=1, but with the dice you won't since the rolls are independent.

... take an experimental approach - play with the setup to see what sort of conditions are possible. get a feel for how the odds work out, and try to use the maths to describe what you learn.
 

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