How Can You Correctly Calculate Forces in a Truss Analysis Problem?

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SUMMARY

The discussion focuses on calculating forces in a truss analysis problem involving a 28kN force and equilibrium equations. The user successfully calculated the vertical reaction force at point B (By = 56kN) by summing moments around point A. However, they encountered difficulties when attempting to solve for the horizontal force at point B (Bx) after summing forces in the x-direction and moments around point C, resulting in an incorrect answer. The user seeks assistance in resolving these issues.

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  • Understanding of static equilibrium principles
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Homework Statement



As shown by the attachment we are given the distances and the 28kN force

Homework Equations



relevant equations are equations of equilibrium;

ƩFy & ƩFx = 0;
ƩM = 0;

The Attempt at a Solution



First found By by summing the moments around point A;
(clockwise positive)
i.e.

ƩMa = (28*0.6) - (By*0.3) = 0

which gave By = 56kN

Next I summed the forces in the x direction and then took the sum of moments around the point "C", then tried to solve the simultaneous equations for Bx

However, this gave the wrong answer and I have no idea where to go.

Any help is great, thanks :D
 

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lecammm said:

Homework Statement



As shown by the attachment we are given the distances and the 28kN force

Homework Equations



relevant equations are equations of equilibrium;

ƩFy & ƩFx = 0;
ƩM = 0;

The Attempt at a Solution



First found By by summing the moments around point A;
(clockwise positive)
i.e.

ƩMa = (28*0.6) - (By*0.3) = 0

which gave By = 56kN

Next I summed the forces in the x direction and then took the sum of moments around the point "C", then tried to solve the simultaneous equations for Bx

However, this gave the wrong answer and I have no idea where to go.

Any help is great, thanks :D
What is the moment about A of the force applied at C by the CB support? What does that tell you about the x component of force at C and at B?

AM
 

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