How Can You Determine Coulomb's Constant from a Force vs. Distance Graph?

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Homework Help Overview

The discussion revolves around determining Coulomb's constant using a force versus separation distance graph, specifically applying the relationship defined by Coulomb's law.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss how to manipulate the force and distance data to create a linear graph that can yield the slope representing Coulomb's constant. There is confusion about the correct representation of the variables on the graph.

Discussion Status

Some participants have offered guidance on how to rearrange the equation to fit a linear model, suggesting that the original poster consider plotting force against a transformed variable. There appears to be a productive exchange of ideas, but no consensus has been reached.

Contextual Notes

The original poster expresses confusion regarding the graphing process and the necessary transformations of the data. There is an indication of a video resource that may have influenced their understanding.

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Homework Statement



Determining Coulomb's constant through a force vs. separation distance graph.

Homework Equations



F = kqQ/r^2

The Attempt at a Solution



So, I'm a little confused about what I should do! We were shown a video of two charges moving towards each other. We were given force/distance data, and I used this to plot a graph. However, I need to make a straight line in the graph...which can be done by working with the equation u = 1/r^2. I've tried using the force values and the distance values but to no avail. I used the distance values as r and then sub those into the x-axis, which is what I did ... so should I simply try to change the scale of the graph ... or something else
 
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Welcome to PF, uflash.
So, you are trying to find the k, right?
The usual approach is to make a graph whose slope is the thing you want to find. You must make F = kqQ/r² look like y = mx so you would choose x to be qQ/r² and y to be F. Then the slope will be k. That is, graph F vs qQ/r² and find the slope.
 
if u =1/r2

then F = ( KqQ ) u , which closely resembles the straight line equation y = mx +b.

where F represents the "y" values, kqQ is the slope, and u represents the "x" values. In this case, the "b" value (y-intercept) equals zero.

so , try substituting u= 1/r2 values into the x-axis to get the solpe .
 
Thank you so much! That really cleared it up for me.
 

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