How Can You Determine the Potential Function of a Conservative Force?

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SUMMARY

The discussion focuses on determining the potential function of a conservative force, specifically through the mathematical conditions that define such forces. It establishes that a force vector \(\vec{F}\) is conservative if the curl of \(\vec{F}\) is zero (rot \(\vec{F} = 0\)) or if it can be expressed as the gradient of a potential function \(U\) (grad \(U = \vec{F}\)). The force is represented as \(\vec{F} = \frac{\vec{r}}{r}\), and the potential function \(U\) can be derived by integrating the components of \(\vec{F}\) with respect to their respective variables. The discussion emphasizes the importance of considering integration constants in multi-variable calculus.

PREREQUISITES
  • Understanding of vector calculus, specifically curl and gradient operations.
  • Familiarity with conservative forces and their properties.
  • Knowledge of multi-variable calculus and integration techniques.
  • Ability to interpret mathematical notation related to force and potential functions.
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  • Study the properties of conservative forces in classical mechanics.
  • Learn about vector calculus operations, particularly curl and gradient.
  • Explore multi-variable integration techniques and their applications in physics.
  • Investigate examples of potential functions for various conservative forces.
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Students and professionals in physics, particularly those studying mechanics, as well as mathematicians focusing on vector calculus and its applications in physical systems.

slonopotam
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to know that a F is a conservative i need to prove that
rot \vec{F}=0
or that grad U=\vec{F}
<br /> \vec{F}=\frac{\vec{r}}{r}<br />

how to know U (potential of F)
??
 
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slonopotam said:
to know that a F is a conservative i need to prove that
rot \vec{F}=0
or that grad U=\vec{F}
<br /> \vec{F}=\frac{\vec{r}}{r}<br />

how to know U (potential of F)
??

Well, if \textbf{F}=\mathbf{\nabla}U=\partial_x U \hat{x}+\partial_y U \hat{y}+\partial_z U \hat{z}=F_x\hat{x}+F_y\hat{y}+F_z\hat{z} (are you familiar with this notation?), then U=\int F_x dx, U=\int F_y dy and U=\int F_z dz must all be true. An important note is that in multi-variable calculus, the 'constants' of integration are only constant with respect to the integration variable, so, for example \int3x^2 dx=x^3+f(y,z)
 

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