How Can You Determine the Potential Function of a Conservative Force?

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slonopotam
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to know that a F is a conservative i need to prove that
rot [tex]\vec{F}=0[/tex]
or that grad [tex]U=\vec{F}[/tex]
[tex] \vec{F}=\frac{\vec{r}}{r}[/tex]

how to know U (potential of F)
??
 
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slonopotam said:
to know that a F is a conservative i need to prove that
rot [tex]\vec{F}=0[/tex]
or that grad [tex]U=\vec{F}[/tex]
[tex] \vec{F}=\frac{\vec{r}}{r}[/tex]

how to know U (potential of F)
??

Well, if [itex]\textbf{F}=\mathbf{\nabla}U=\partial_x U \hat{x}+\partial_y U \hat{y}+\partial_z U \hat{z}=F_x\hat{x}+F_y\hat{y}+F_z\hat{z}[/itex] (are you familiar with this notation?), then [itex]U=\int F_x dx[/itex], [itex]U=\int F_y dy[/itex] and [itex]U=\int F_z dz[/itex] must all be true. An important note is that in multi-variable calculus, the 'constants' of integration are only constant with respect to the integration variable, so, for example [itex]\int3x^2 dx=x^3+f(y,z)[/itex]