How Can You Linearise a Cosine Curve for g-forces in Physics?

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SUMMARY

The discussion centers on the linearization of the formula for g-forces, expressed as g-forces = √(391.88 - 337.12 cosθ) / 9.8. The key challenge is determining the appropriate independent variable for linearization, specifically whether to use the angle θ or cos(θ). A critical insight is that the expression (391.88 - 337.12 cosθ) remains non-negative, allowing for valid square root calculations across the defined range of cos(θ).

PREREQUISITES
  • Understanding of trigonometric functions, specifically cosine.
  • Familiarity with the concept of linearization in mathematics.
  • Knowledge of the properties of square roots and their domains.
  • Basic physics concepts related to g-forces and their calculations.
NEXT STEPS
  • Research the method of linearizing equations in the form y = k√(x).
  • Explore the implications of the range of the cosine function on physical formulas.
  • Study graphical representations of trigonometric functions and their transformations.
  • Investigate the application of linear regression techniques to experimental data in physics.
USEFUL FOR

Students and educators in physics, particularly those working on experimental investigations involving g-forces and mathematical modeling of trigonometric functions.

Maluras
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Homework Statement



For my physics EEI, I have developed the formula: g-forces=√(391.88-337.12 cosθ)/9.8

I need to linearise the graph into the form y=mx+c.

I'm not sure where just the angle is the independent or cos of the angle.

Homework Equations



y=k√(x) can be graphed as y vs. √(x) to linearise

The Attempt at a Solution



The square root of a negative is undefined, therefore √(cosθ) is unable to be done for all values
 
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Maluras said:

Homework Statement



For my physics EEI, I have developed the formula: g-forces=√(391.88-337.12 cosθ)/9.8

I need to linearise the graph into the form y=mx+c.

I'm not sure where just the angle is the independent or cos of the angle.

Homework Equations



y=k√(x) can be graphed as y vs. √(x) to linearise

The Attempt at a Solution



The square root of a negative is undefined, therefore √(cosθ) is unable to be done for all values
Hello Maluras. Welcome to PF !

Is (391.88-337.12 cosθ ) ever negative?

-1 ≤ cos(θ) ≤ 1

Multiply by -337.12 then add 391.88 .

What's your conclusion regarding the range of (391.88-337.12 cosθ ) ?
 

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