How Close to Speaker B Causes Destructive Interference at 172 Hz?

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SUMMARY

The discussion addresses the calculation of the closest distance to speaker B for achieving destructive interference of sound waves emitted at 172 Hz from two loudspeakers, A and B. The wavelength of the sound is determined to be 2 meters, leading to the conclusion that the closest distance to speaker B for destructive interference is 1 meter. This is derived from the condition that the path length difference must equal half a wavelength, specifically using the formula d_a - d_b = n(wavelength)/2, where n=1 for the shortest distance. The distance from speaker A is given as 8 meters.

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  • Familiarity with basic trigonometry and distance calculations.
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[SOLVED] Interference of Sound Waves

Two loudspeakers, A and B, are driven by the same amplifier and emit sinusoidal waves in phase. The frequency of the waves emitted by each speaker is 172 Hz. You are 8.00 m from speaker A. Take the speed of sound in air to be 344 m/s.
What is the closest you can be to speaker B and be at a point of destructive interference?
__________I am having the hardest time trying to visualize the problem. I know that destructive interference occurs when the difference in path lengths traveled by sound waves is a half integer number of wavelengths. So I need to know the wavelength of the sound which is just 2m.

I also know that in general if d_a and d_b are paths traveled by two waves of equal frequency that are originally emitted in phase, the condition for destructive interference is d_a-d_b=n(wavelength)/2 where wavelength is what I calculated it to be (2m) and n=any nonzero odd integer. I think I need to know what the value of n is that corresponds to the shortest distance d_b to solve my prob. (is d_a=8m? then what is d_b?)

I'm going around in circles and getting nowhere. Please help!
 
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Take n=1 for shortest distance from speaker B.
 
Usually, it is important to know the distance between the two speakers. Is this not given?

Then you can move B wherever you like. If you are 8 m from A, and wavelength is 2 m, the sound form A has traveled 4 full integer multiples of the wavelength. You must place B at a location such that the sound will arrive 1/2 wavelength out of phase. One full wavelength? or less? how much less?
 
apparently n=1 is not the right answer.

all info has been given.

gahh. i need help. Yes, sound from A has traveled 4X the wavelength of sound emitted by the loud speakers. Sound from B must be moved so that the sound arrives 1/2 wavelength out of phase (d_a-d_b=n(wavelength)/2) so are you telling me the same thing that Vijay told me, that n=1?
 
am i approaching this the wrong way? ..Nobody??
 


The correct answer is 1.00m.
Hint: The closest you can be to B. (lamda/2)
 

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