How Do Capacitors Store Charge in Different Configurations?

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SUMMARY

The discussion focuses on the charge storage capabilities of three capacitors (C1, C2, and C3) connected in a circuit with a battery. Capacitor values are C1 = 3C, C2 = C, and C3 = 5C, with C2 and C3 connected in parallel and then in series with C1. The correct ranking of the capacitors according to the charge they store, from largest to smallest, is C1 > C3 > C2. This conclusion is derived from the relationship between charge (Q), capacitance (C), and voltage (V) in the circuit configuration.

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Homework Statement


Circuit diagram: a battery connects three capacitors in the following way.

Connects two capacitors in "parallel" and ends the circuit by connecting a capacitors in series.

C2
batteries { } C1 -> back to battery
C3

C1 = 3C
C2 = C
C3 = 5C

Question: State the ranking of the capacitors according to the charge they store, from largest to smallest.


Homework Equations



V = Q / C ?
Q1/Q2 = C1/C2 ?

The Attempt at a Solution


I combined C2 and C3... so let C4 be the combination of C2 and C4

battery -> C4 -> C1 -> back to battery
Q1/Q4 = C1/C4
Q1/Q4 = 3C/6C

? but I think I am wrong... because the solution says that Q1 = greatest
 
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um, i don't know why the circuit looks different than I organized in the text earlier... so please ignore

C2
batteries { } C1 -> back to battery
C3
 
Okay, nevermind... I have done more readings online and found the answer. Thanks anyway =)
 

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