How Do Circuit Currents Distribute in Complex Networks?

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Homework Help Overview

The discussion revolves around analyzing current distribution in a complex circuit network involving multiple nodes and resistors. The original poster is attempting to apply Kirchhoff's Voltage Law (KVL) and is confused about the current flow at specific nodes, particularly regarding the contributions from a current source and the voltage across resistors.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster questions whether the entire 1A current flows into node 2 or if part of it goes through another resistor. They seek clarification on how to determine the current contribution from the source. Other participants suggest writing equations based on known voltages and currents, and express the need to consider the direction of current flow based on potential differences.

Discussion Status

Participants are actively working through equations and discussing the correctness of their setups. Some guidance has been offered regarding the application of Kirchhoff's Current Law (KCL) and the importance of sign conventions in the equations. There is an ongoing exploration of the relationships between voltages and currents, but no consensus has been reached on the correctness of the calculations.

Contextual Notes

There is mention of a discrepancy between the original poster's calculated current and the value provided in a textbook, leading to further questioning of the setup and assumptions made in the analysis. Participants are also addressing potential errors in the equations due to sign conventions.

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Homework Statement


[PLAIN]http://img195.imageshack.us/img195/7725/1038d.png

Homework Equations



KVL.

The Attempt at a Solution



I'v set up the equation for node v1 node, but v2 node confuses me.

would it be correct to assume that the 1A current flows into node 2? Or does only part of it flow into node 2, (with the other part going down the 10 ohm resistor into ground)

How do i find out how much current that 1A source is contributing into node 2.

Also when setting up the KVL for node 1, i have (v1/5ohms) + (v1 - v2)/5ohms... but i can't figure out the current coming through the 10v Voltage source to V1. I coudl do V1-V2, and then divide it by the resistance of the voltage source. but i don't know the resistance of the voltage source.

please help
 
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You know the voltage across the resistor between the nodes v2 and v1: it is 10 V. What is the magnitude and direction of the current flowing through it?

The nodes at v2 are connected with a single wire so they can be replaced by a single node. Write the sum of currents for it. Do not forget to include is.

You know the relation between the voltages: v1=v2+10. Express the current flowing between v1 and the ground through the left 5 ohm resistor.

Write an equation for the currents at the node at v1, including is .

These equation must be enough to get the unknown voltages and currents.

ehild
 
After working through it, the answer i got for Is was -4A.

The book however says -3.33A. But this book has been wrong before. Have i made a mistake, or is the book wrong. I looked through my working and didn't spot anything mathamatically incorrect, but it's multiple pages in length.
 
The book is correct. And the solution is just a few lines. Try to follow my post.

ehild
 
Hmm.. I seem to be doing something wrong.

here are my two equations:

at V1 I have

(V1/5) + Is -2 = 0

and at V2 i have

Is + 2 + (v2/10) +1 = 0

Does this look right?
 
You're close but both expressions have an error due to incorrect sign/s.

I like to think of using KCL as: sum of current coming in = sum of current going out

Edit: Oh, and you're forgetting Is at V2
 
Learnphysics said:
Hmm.. I seem to be doing something wrong.

here are my two equations:

at V1 I have

(V1/5) + Is -2 = 0

and at V2 i have

Is + 2 + (v2/10) +1 = 0

Does this look right?

No. Remember the current flows in the direction of the electric field which is proportional to the negative potential difference, from a place at a more positive potential to the negative one. You know that the potential at the left terminal of the top 5 ohm (v1) resistor is 10 V higher than that of the right terminal. So the current flows from left to right. At the 10 ohm resistor: The upper end is at v2 potential, the lower one is at 0 potential. The current flows from the node v2 to the ground.

ehild
 

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