How do current of the circuit affect the magnitism of the nail

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SUMMARY

The discussion focuses on the relationship between electric current and the magnetism of a nail wrapped with wire. When current flows through the coil around the iron nail, it induces a magnetic field along the nail's length, creating a North-South magnetism. If the coil is insulated, increasing current leads to a steady-state condition where the nail becomes magnetized in alignment with the coil's magnetic field. The magnetic field strength is generally proportional to the current, with exceptions for specific materials and conditions.

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I am doing a lab these days
its about how the current of the circuit affect the magnitism of the nail (rapped with wire around it)
I wonder if anyone has the relation or some info related to it.
 
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I think your question is unclear, but I will make an assumption that i know what you are asking and proceed. please correct me if wrong.

assumption: you have wrapped a coil around a conducting (iron) nail, and are passing current through the coil.

well, if there is no insulation between the two, you effectively have a short circuit.

if there is an insulation, as the the current in the coil increases, it will induce an opposite sense current in the nail to try to cancel out the growing flux of the coil. when the current becomes steady state, no more current will flow in the nail. Accordingly, you will have created a N-S magnetism field along the length of the nail.

now conducting materials like the nail are theorized to be ferromagnetic materials. i.e., they are said to include dipoles that are highly susceptible to magnetic fields. As you can imagine, your current carrying coil will magnetize the nail in the same sense as the coil was magnetized.

More about ferromagnetism here:http://en.wikipedia.org/wiki/Ferromagnetic
 
Last edited:
In 99% of cases the magnetic field strength is proportional to the current in the wire, the exceptions are for more complicated materials/conditions.
 

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