How Do Helper Springs Work in Truck Suspensions?

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Homework Help Overview

The discussion revolves around the mechanics of helper springs in truck suspensions, specifically focusing on a problem involving the compression of leaf and helper springs under load. The original poster seeks guidance on how to approach the problem involving spring constants and load calculations.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants explore the relationship between load and spring compression, questioning how to set up the problem and what happens when the load exceeds the threshold of the leaf spring. There is discussion about how to handle the remaining load once the threshold is reached.

Discussion Status

Some participants have offered insights into the calculations needed to determine the compression of the springs and how the load is shared between them. The conversation is ongoing, with multiple interpretations of how to distribute the load being explored.

Contextual Notes

The original poster expresses uncertainty about the setup of the problem and the calculations involved, indicating a need for clarification on the mechanics of spring compression under load.

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5. [SerCP7 5.P.022.] Truck suspensions often have "helper springs" that engage at high loads. One such arrangement is a leaf spring with a helper coil spring mounted on the axle, as shown in Figure P5.22. When the main leaf spring is compressed by distance y0, the helper spring engages and then helps to support any additional load. Suppose the leaf spring constant is 5.30 105 N/m, the helper spring constant is 3.60 105 N/m, and y0 = 0.500 m.

Figure P5.22

(a) What is the compression of the leaf spring for a load of 4.90 x 10^5 N?

(b) How much work is done in compressing the springs?
J


I am really not sure where to begin or how to set up this spring problem... Any help is greatly appreciated...thank you!
 
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Well, weight is force due to gravity, so let W = F = kx, or x = W/k.

So, if the leaf spring were to handle the entire load, what would x be?

If x > 0.5 m, the "helper spring" then shares the load.

So how much of the load corresponds to deflection of 0.5 m?

Then the remainder of the load is shared between the springs.
 
thanks a lot. that really helps.
 
If I find the W or F(x) required to compress the spring to its threshold of 0.5m, and minus that from the total load applied to the spring leaf, what do I do with the remaining load? Do I divide it equally between the leaf spring and the helper spring since they are sharing the remaining load?
Thanks so much!
 

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