russ_watters
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Yes, that's my point: In order for the water to do work, the piston has to move.A.T. said:But the piston is not moving if the fluid is incompressible.
It lies in the fact that you're double-counting the gravitational potential energy. In the hyperphysics page on Bernoulli's equation, it lists 3 pressures:And my question is, where exactly the error lies.
-Static pressure
-Velocity pressure
-Hydrostatic pressure
The pressure at the bottom of a hydro dam is hydrostatic pressure, but you're making the mistake that if you can measure it with a pressure gauge, it must be static pressure, so you're double-counting it. For your example of putting a weight on a volume of water, you've substituted that weight for the extra water column, changing nothing: you're still double-counting gravitational potential energy by using the static pressure term when it doesn't apply.
You shouldn't: the equation isn't doing that, you are.I don't quite see how you can claim that pressure_energy and potential_energy represent the same quantity here. Why would you count the same thing twice?
Yes. And in both the case of the hydro dam and the case of your piston-cylinder-weight, the [static] pressure energy is zero (if you consider the weight to still have its gpe).That is how I understand it too. And pressure energy is something different, that is accounted for separately.