How do I calculate a triangle coordinate?

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The discussion focuses on calculating the coordinates of the third corner of a triangle (Corner A) when the coordinates of two corners (B and C) and the area are provided. Given the area of triangle ABC as 14994 sqm, Corner B at (+3541.620, -5467.650) and Corner C at (+3300.580, -5503.150), the calculation reveals that the solution is not a single coordinate but rather a function representing the locus of possible coordinates for Corner A. The area can be determined using the formula Area = 1/2 |AB × AC|, emphasizing the relationship between the triangle's area and its vertex coordinates.

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1. Calculate the coordinate of a triangle's 3rd corner when 2 corner coordinates and area is given (in Surveying).
Given:
Area of triangle ABC = 14994sqm
Corner B coordinate = +3541.620 (Y); -5467.650 (X)
Corner C coordinate = +3300.580 (Y); -5503.150 (X)

Calculate corner A's coordinates?
I know how to calculate the area of a triangle by using the 3 coordinates, but for some or other reason the reverse of this equation doesn't work?
 
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I've been away from math too long to actually sit down and DO this problem, but the one thing that you seem to be not understanding, based on your statement of the problem, is that there is no single coordinate. That is, the answer is not a coordinate. The answer is a function describing the locus of the 3rd coordinate, of which there are an infinite number (although they might be on a bounded curve).
 
If you know how to work with cross product you can use the formula:

[tex]Area=\frac{1}{2}|AB \times AC|[/tex]

But the answer will be a function.
 

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