arroy_0205 Messages 127 Reaction score 0 Thread starter Dec 9, 2010 #1 The group SO(5) is relevant at times in particle physics. Can anybody please explain how to calculate the number of generators of SO(5)?
The group SO(5) is relevant at times in particle physics. Can anybody please explain how to calculate the number of generators of SO(5)?
chrispb Messages 100 Reaction score 1 Dec 9, 2010 #2 With SO(n), you can rotate axis 1 into axes 2, 3,...,N. With axis 2, you can rotate it into 3,...N. So, SO(n) has (N-1)+(N-2)+...+1 = N(N-1)/2 generators. So, SO(2) has 1, SO(3) has 3, SO(4) has 6 and SO(5) has 10. Hope this helps.
With SO(n), you can rotate axis 1 into axes 2, 3,...,N. With axis 2, you can rotate it into 3,...N. So, SO(n) has (N-1)+(N-2)+...+1 = N(N-1)/2 generators. So, SO(2) has 1, SO(3) has 3, SO(4) has 6 and SO(5) has 10. Hope this helps.
arroy_0205 Messages 127 Reaction score 0 Dec 10, 2010 #3 Thanks a lot for your reply. I understand this now.