The discussion revolves around calculating the internal resistance in a circuit, specifically in the context of a problem involving a 3V source and a 5-ohm resistor. The original poster expresses difficulty in starting the problem and lacks initial working or solutions.
Some participants have offered guidance on how to visualize the internal resistance of the battery and suggested drawing the circuit to better understand the relationships between components. There is an ongoing exploration of the calculations and their implications, with no explicit consensus reached yet.
The original poster has not provided any working or solutions, which may limit the discussion's depth. The problem's specifics, such as the exact configuration of the circuit, are not fully detailed, leading to assumptions that are being questioned.
Integral said:You know the voltage drop across the 5ohm resistor therefore you can find the current. Now what resistance is needed to yield that current with a 3V source?
tweety1234 said:but how do i show its 0.4 ohms?
0.4 + 5 = 5.4
3/5.4 = 0.55 amps? is this correct?