How do I calculate work and heat in a PV diagram for an ideal monoatomic gas?

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Homework Help Overview

The discussion revolves around calculating work and heat in a PV diagram for an ideal monoatomic gas, focusing on the processes involved in a transition from point A to point C. Participants are exploring the implications of the ideal gas law and the first law of thermodynamics in this context.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to determine the work done by the gas during various processes and whether it is simply the sum of work done in each segment. Questions arise about the nature of the process (cyclic or not) and the implications for internal energy changes.

Discussion Status

There is an ongoing exploration of the specific processes involved in the transition from A to C, with some participants suggesting that the focus should be on the segments between A and B, and B and C. Guidance has been offered regarding the distinction between thermodynamic quantities and their changes, and some participants are clarifying their understanding of specific heat in relation to the gas type.

Contextual Notes

Participants are working with the assumption that the gas is ideal and monoatomic, which influences their calculations of specific heat and internal energy. There is also a noted lack of clarity in the problem statement regarding the processes involved.

Muthumanimaran
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Homework Statement


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Homework Equations


Ideal gas law:
$$PV=nRT$$

Workdone by the gas:
For Isobaric process
$$W=P(V_{2}-V_{1})$$

For Isothermal Process
$$W=nRT \ln(V_{2}{/}V_{1})$$

First law:
$$U=Q-W$$

The Attempt at a Solution


subpart (a) is trivial, all we have to do is to substitute the given data in Ideal gas law to get the temperatures.

I have conceptual difficulty in part (b) and (c)only
The PV diagram conists of two Isothersms (DA and BC) and two Isobars (AB and CD)
How to calculate workdone by the gas?
Is it just the sum of the workdone by four processes ?

Next, Heat absorbed by gas?
Since the total Internal energy U of a cyclic process is zero, is it just equal to the total workdone?
 

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Muthumanimaran said:
How to calculate workdone by the gas?
Is it just the sum of the workdone by four processes ?
No. You are told that the system goes from A to C along path ABC. Which processes does that involve?
Muthumanimaran said:
Next, Heat absorbed by gas?
Since the total Internal energy U of a cyclic process is zero, is it just equal to the total workdone?
Is this a cyclic process?
(By the way, your statement is wrong in any case. The total internal energy change, ΔU, of a cyclic process is zero. It is vitally important to distinguish between thermodynamic quantities and changes in those quantities. Many mistakes are made here.)
 
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I think the focus of this problem is only the portion of the path between A and C. From the information given, you also know the volume at B. What is that volume?
 
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Oh, I got it now. I just need to calculate the work done from A to B and B to C and sum it up? Am I right?
 
Muthumanimaran said:
Oh, I got it now. I just need to calculate the work done from A to B and B to C and sum it up? Am I right?
That's my interpretation of the problem statement. Arguably, it is not very clear.
 
From A to C it is not a cyclic process, so the change in internal energy cannot be zero (from A to C), then how to find the heat absorbed by the gas?
 
What is the pressure, volume, and temperature of the gas at C? What is the pressure, volume, and temperature of the gas at B?
 
P=1 atm V=20lit at point C and T=PV/R

So T=20/R K at point C

Pressure at B is 4 atm T = 20/R
So V=5 lit
 
Without knowing the specific heat of the gas how do I calculate the change in internal energy from A to B? Workdone = P(VB-VA), is it just enough to plug these values to find the heat transfer from A to B? for B to C is an isotherm, so workdone is equal to heat right?
 
  • #10
Muthumanimaran said:
P=1 atm V=20lit at point C and T=PV/R

So T=20/R K at point C

Pressure at B is 4 atm T = 20/R
So V=5 lit
You do know the value of R, correct.? Please provide actual numbers for the temperatures at A, B, and C.
 
  • #11
Muthumanimaran said:
Without knowing the specific heat of the gas how do I calculate the change in internal energy from A to B? Workdone = P(VB-VA), is it just enough to plug these values to find the heat transfer from A to B? for B to C is an isotherm, so workdone is equal to heat right?
You are told that the gas is an ideal monoatomic gas. What does that tell you about its specific heat?
 
  • #12
Chestermiller said:
You are told that the gas is an ideal monoatomic gas. What does that tell you about its specific heat?
Specific heat is (3/2)R. Now I got it.
 

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