How do I check if a 1x1 matrix is diagonal, lower/upper triangular?

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A 1x1 matrix is inherently both upper and lower triangular, as it contains only one element, a11. For a matrix to be strictly upper or lower triangular, the value of a11 must be zero. A matrix is considered diagonal if it has no nonzero entries off the diagonal, which is trivially satisfied by a 1x1 matrix since there are no off-diagonal entries. Therefore, any 1x1 matrix is diagonal, upper triangular, and lower triangular, with the exception of strict triangularity when a11 is nonzero. In conclusion, a 1x1 matrix meets the criteria for all three classifications based on the value of a11.
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I have an A matrix with dimensions 1x1. Its the only term a11 is an arbitrary number.

For what values of a11, this A matrix is;

  1. Diagonal
  2. Upper triangular
  3. Lower triangular
 
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hkBattousai said:
I have an A matrix with dimensions 1x1. Its the only term a11 is an arbitrary number.

For what values of a11, this A matrix is;

  1. Diagonal
  2. Upper triangular
  3. Lower triangular

By definition a 1x1 matrix will be upper and lower triangular. (But not strictly; for strictly upper and lower: a must be 0).

A matrix is diagonal if it is triangular and normal. Normal (for a matrix whose elements lie in the domain of real numbers) means A \ A^T = A^T \ A
 
A matrix is diagonal if it has no nonzero entries off the diagonal. A matrix is upper triangular if it has no nonzero entries below the diagonal. etc.

Clearly any 1x1 matrix satisfies these properties, since there are no entries off the diagonal, nonzero or not.
 
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