How do I convert 1.2atm to N/m^2 when solving for gas work?

[HazyMan]

<Moderator's note: Moved from a technical forum and thus no template.>

My homework says: Gas with a volume of 0.004m^3 is heated with a steady pressure of 1,2atm until the volume turns into 0.006m^3. Calculate the work that the gas produces (Given: 1atm=1,013x10^5 N/m^2).

I used the Isobaric Expansion Work formula W=p(V2-V1) and i managed to get to W=1,2atm x 0.002m^3, however atm and m^3 are not in the same system. I am trying to convert 1.2atm into N/m^2 but i can't find anything on the internet, so i came here asking for help. Where can i find a guide to do this conversion? Is it even possible, is it needed to convert to Pa instead?

 

[stockzahn]

1 Pa = 1 N/m²
1 atm = 1.01325 bar
1 bar = 10⁵ Pa

 

[jbriggs444]

(Given: 1atm=1,013x10^5 N/m^2)

I am trying to convert atm into N/m^2

It looks to me as if you had answered your own question before asking it.

[Personally, being an ancient U.S. relic, I'd have taken 14.7 pounds per square inch, converted pounds to kilograms-force to Newtons and square inches to square meters]

 

[DrClaude]

https://www.wolframalpha.com/input/?i=convert+atm+to+N/m^2

 

[HazyMan]

It looks to me as if you had answered your own question before asking it.

i'm trying to convert 1,2atm into N/m^2. not 1atm.

 

[jbriggs444]

i'm trying to convert 1,2atm into N/m^2. not 1atm.

Most calculators give you the ability to multiply by 1,2

 

[HazyMan]

Most calculators give you the ability to multiply by 1,2

i know, i'd just like to do it manually.

 

[jbriggs444]

i know, i'd just like to do it manually.

   1,013 x 10^5
x  1,2
   -----
   1,013
   + 2026
   ------
   1,2156 x 10^5

Long multiplication by 1,2 is not much harder than a calculator.

 

[HazyMan]

   1,013 x 10^5
x  1,2
   -----
   1,013
   + 2026
   ------
   1,2156 x 10^5

Long multiplication by 1.2 is not much harder than a calculator.

Thanks.