How Do I Correctly Calculate Vector C Using Unit Vectors?

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To calculate vector C using unit vectors, first express vectors A and B in terms of their components: A = 1.23i + 3.38j and B = -1.2i - 2.1j. For part B, substitute these values into the equation C = 3A - 4B. This results in C = 3(1.23i + 3.38j) - 4(-1.2i - 2.1j), which needs to be expanded and simplified. The correct calculation should yield a final expression for vector C in the form of a combination of i and j components. Accurate calculations are essential for determining the magnitude and direction of vector C in part C.
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Homework Statement



Here's the entire question. But I ONLY NEED help with part B. Part A and Part C I know how to do:

Vector A is 3.60 m with an angle of 70 degrees and Vector B is 2.4 m with an angle of 30 degrees downward.

a) Write Vector A and Vector B in terms of the unit i and j (already completed)

b) Use unit vectors express vector C where vector C = 3.00A-4.00B

c) Find the magnitude and direction of Vector C

Homework Equations


Vector addition..

The Attempt at a Solution



Here's the solution for part A.

Vector A= 3.60sin70=3.38
3.60cos70=1.23
so Vector A in terms of i and j= 1.23i + 3.38j

Vector B= 2.4sin30=1.2
2.4cos30=2.1
so vector B in terms of i and j= -1.2i + -2.1j (negative since going down)

For part b, I did trial and error, however when I looked at the answer in the back of the book, it was completely wrong. The answer is 12.01i + 14.94j and the numbers I got is much lower. I cannot do part C without getting part B first. Help!
 
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It says C = 3A - 4B
Replace A with your answer (1.23i + 3.38j) and B with your (-1.2i - 2.1j).
Expand and simplify. The final answer should be a number times i plus a number times j.
 
If angles are measured positive counter-clockwise from the positive x-axis (as standard) then your value for B is incorrect.
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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