How do I determine if it's a Hermitian Operator or not

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Homework Help Overview

The discussion revolves around determining whether specific operators, such as i(d/dx) and (d^2)/(dx^2), are Hermitian operators in the context of quantum mechanics. Participants reference the definition of Hermitian operators and express uncertainty about applying this definition in practical examples.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the process of using integrals and integration by parts to test the Hermitian property of operators. There are questions about the evaluation of integrals involving second derivatives and the implications of boundary conditions.

Discussion Status

Some participants have provided guidance on using integration by parts, while others express confusion about specific steps and concepts, such as integration by parts and the evaluation of certain integrals. There is an ongoing exploration of the necessary conditions for an operator to be Hermitian.

Contextual Notes

Participants mention the need to consider boundary conditions and the definitions of operators, as well as the implications of the operators being densely defined or bounded. There is also a reference to a specific textbook, Griffiths' "Intro to Quantum Mechanics," which some feel lacks detailed steps.

MixilPlixit
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First post so please go easy on me, here goes:

I have looked over the basic definition of what is a Hermitian operator such as: <f|Qf> = <Qf|f> but I still am unclear what to do with this definition if I am asked prove whether or not i(d/dx) or (d^2)/(dx^2) for example are Hermitian operators. I am using Griffiths' "Intro to Quantum Mechanics" and it really seems like he skips a lot of steps. Steps I need to make sure I understand. Can someone help enlighten me.
 
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You have to put the operator in the integral \int\psi*[id/dx]\psi dx.
Then integrate by parts, using the BC at the endpoints. If you get the same result after integratilng by part, the operator is hermitian.
 
Meir Achuz said:
You have to put the operator in the integral \int\psi*[id/dx]\psi dx.
Then integrate by parts, using the BC at the endpoints. If you get the same result after integratilng by part, the operator is hermitian.

This is exactly how it's done in Griffiths too. Maybe Mixil had some specific part of this in mind?
 
I think I am a little hazy on integration by parts, so that apeears to be where my problem lies. Can someone recommend a good refresher on the matter?
 
http://archives.math.utk.edu/visual.calculus/4/int_by_parts.3/
I just found this on google, and it appears to be a nice introduction, and takes you through each step. Perhaps a little basic for what you want though?
Hope it helps,
~Gareth
 
OK, that somewhat helps but if I have \int \frac{d^2}{d \phi^2}d \phi how do I evaluate that? It's been a while since calc obviously. It's the 2nd derivative thing that's throwing me. Hopefully I am not tiring you guys, cause I am certainly getting bleary. Thanks for your help this far. I am thankful for your continued assistance.
 
MixilPlixit said:
OK, that somewhat helps but if I have \int \frac{d^2}{d \phi^2}d \phi how do I evaluate that?

You can't evaluate that. On what is \frac{d^2}{d \phi^2} operating?

Regards,
George
 
I am given Q = \frac{d^2}{d \phi^2} And am asked to prove if eigenvalues are real. In order to do that I need to determine if Q is in fact a Hermitian operator. So I am at: \int f*(\frac{d^2}{d \phi^2})g d\phi This is integrated over 0 to 2 pi.
 
Last edited:
You need to use integration by parts twice. For the first integration by parts, it may be helpful to think of

\left( \frac{d^2}{d \phi^2} \right)g

as

\frac{dg&#039;}{d \phi}

where

g&#039; = \frac{dg}{d \phi}.

Regards,
George
 
  • #10
For the first integration then would v = \frac{dg}{d \phi} and du = (\frac{df}{d\phi})^*?

[edit] Well I think I solved it, but it feels wrong. I got -\int f^*(\frac{d^2}{d \phi^2}) g d\phi It the initial integral but minus. Can that be right?
 
Last edited:
  • #11
Assuming the operator is densly defined, can u at least identify the operator's adjoint...? Next thing to worry you is to find whether your operator is bounded or not...

Daniel.
 

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