How do I determine the center of mass for a rod with varying linear density?

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Homework Help Overview

The discussion revolves around determining the center of mass for a rod with a varying linear density defined by the equation λ = 50.0 + 21.5x, where x represents the distance from one end of the rod. The problem includes calculating the total mass and finding the center of mass from a specified point.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the integration of the density function to find total mass and explore the concept of finding an x-value where the mass to the left of that point equals the mass to the right. There are attempts to set up integrals to represent these conditions.

Discussion Status

The discussion includes various approaches to setting up integrals for calculating the center of mass. Some participants express confusion about the mathematical steps involved, while others provide insights and affirm the validity of the proposed methods. There is an acknowledgment of the usefulness of calculus in solving the problem.

Contextual Notes

Participants reference the need for calculus techniques to solve the problem, indicating a potential gap in knowledge or recall of methods. The original poster has successfully calculated the total mass but is seeking further clarification on the center of mass calculation.

aborder
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Homework Statement



A rod of length 36.00 cm has linear density (mass per length) given by
λ = 50.0 + 21.5x

where x is the distance from one end, and λ is measured in grams/meter.

A. Find Total Mass
B. Find center of mass from x=0

Homework Equations



1/M(integral)xdm , where M is total mass

The Attempt at a Solution



So I figured the total mass was the just the integral of the given density equation. Which was correct and part A was found to be 50x + 21.5x^2/2. Substituting in makes gets 19.39g (the right answer.) But I am confusing how to find the total mass with the necessary calculus requred to determine the center of mass. The issue I am having is with determining the center of mass.
 
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Can you find an x-value where the mass to its left = the mass to its right?
 
NascentOxygen said:
Can you find an x-value where the mass to its left = the mass to its right?

That sounds like a good idea conceptually, but I'm not sure how to figure this mathematically.
 
Integral from 0 to x0 = integral from x0 to 0.36
 
NascentOxygen said:
Integral from 0 to x0 = integral from x0 to 0.36

Well that worked most excellently. Thank you. How did you see to do that?
 
I guess I've encountered a problem like that once or twice before. :smile:

I found calculus to be a breath of fresh air. :!) :!) The things it can do seemed limitless. Calculus is like the Swiss army knife of mathematics--a tool with no limit to its practical uses, as well as satisfying endless hours of intellectual amusement. :approve: :approve: :approve:

Unfortunately, I've forgotten most of the techniques, and now just retain admiration for the concept. :blushing:
 
aborder said:
Well that worked most excellently. Thank you. How did you see to do that?
There is a point on the rod where the mass to the left equals the mass on the right. He chose an arbitrary point where this is the case. Setting the integrals equal to each other and solving like you did for total mass, then using Algebra you should be able to solve for x0.
 

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