How do I differentiate this Scalar Field?

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The discussion centers on differentiating a scalar field and the application of covariant derivatives. The user successfully found the Christoffel symbols but struggles with the second covariant derivative of the scalar field, questioning the relationship between covariant and partial derivatives. It is clarified that while the first covariant derivative of a scalar field is indeed a normal derivative, the second derivative involves Christoffel symbols due to its action on a covector field. The conversation emphasizes the need to rewrite the expression for clarity and correct application of covariant derivative rules. Understanding these concepts is essential for solving the problem effectively.
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Homework Statement



(a) Find the christoffel symbols (Done).
(b) Show that ##\phi## is a solution and find the relation between A and B.[/B]

2013_B5_Q2.png

Homework Equations

The Attempt at a Solution


Part(b)
\nabla_\mu \nabla^\mu \phi = 0
I suppose for a scalar field, this is simply the normal derivative:
\frac{\partial^2 \phi}{\partial \eta^2} + \frac{\partial^2 \phi}{\partial r^2} = 0

Starting with the ##\eta## component:
\frac{\partial \phi}{\partial \eta} = exp() \left[ B + (A+B\eta)(-ic|k|) \right]
\frac{\partial^2 \phi}{\partial \eta^2} = exp() \left[ -2ic|k|B - |k|^2c^2(A+B\eta) \right]

Now for the ##r## component:
\frac{\partial \phi}{\partial r} = exp() \left[ A+B\eta \right](\vec k \cdot \hat r)
\frac{\partial^2 \phi}{\partial r^2} = exp() \left[ -(A+B\eta)(\vec k \cdot \hat r)^2 \right]

Equating both real parts doesn't work; It gives ##(\vec k \cdot \hat r)^2 = |k|^2 c^2##..
 
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What is ##\nabla_\mu## here? I would have thought they'd be covariant derivatives, not partial derivatives. (?)

Even though a covariant derivative of a scalar field is just the partial derivative, the 2nd covariant derivative is acting on a vector...
 
strangerep is correct, the second covariant derivative is not acting on a scalar, but on a covariant vector. I suggest rewriting it as
$$
\nabla^\mu \nabla_\mu \phi = g^{\mu\nu} \nabla_\mu \nabla_\nu \phi
$$
and apply the rules for covariant derivatives from there.
 
Orodruin said:
strangerep is correct, the second covariant derivative is not acting on a scalar, but on a covariant vector. I suggest rewriting it as
$$
\nabla^\mu \nabla_\mu \phi = g^{\mu\nu} \nabla_\mu \nabla_\nu \phi
$$
and apply the rules for covariant derivatives from there.

I know that for a vector field, ##\nabla_\alpha V^\mu = \partial_\alpha V^\mu + \Gamma^\mu_{\alpha \gamma} V^\gamma##. Does this apply to scalar fields as well? Or in the case of a scalar field, does it simply reduce to a normal derivative?

I have also found that
\nabla_\alpha \nabla_\beta V^\mu = \partial_\alpha \partial_\beta V^\mu + \left(\partial_\alpha \Gamma^\mu_{\beta \nu} \right)V^\nu + \Gamma^\mu_{\beta \nu} \left( \partial_\alpha V^\nu \right) + \Gamma^\mu_{\alpha \nu} \left[ \partial_\beta V^\nu + \Gamma^\nu_{\beta \epsilon} V^\epsilon \right] + \Gamma^\nu_{\alpha \beta} \left[ \partial_\nu V^mu + \Gamma^\mu_{\nu \epsilon} V^\epsilon \right]
 
unscientific said:
I know that for a vector field, ##\nabla_\alpha V^\mu = \partial_\alpha V^\mu + \Gamma^\mu_{\alpha \gamma} V^\gamma##. Does this apply to scalar fields as well? Or in the case of a scalar field, does it simply reduce to a normal derivative?

No, for scalar fields you have ##\nabla_\mu \phi = \partial_\mu \phi##. However, ##\nabla_\mu \phi## is a covector field and as such its covariant derivative ##\nabla_\nu\nabla_\mu \phi## will involve a Christoffel symbol.
 
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