How do I Find Average Force in a Force vs Time graph?

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SUMMARY

The average force in a Force vs Time graph can be determined by calculating the area under the curve, which represents impulse (the change in momentum). The time-averaged force is the constant force that would produce the same change in momentum over the same time interval. To find this, divide the total impulse by the total time. This method applies to graphs that increase, remain constant, and then decrease in force.

PREREQUISITES
  • Understanding of impulse and momentum concepts
  • Familiarity with Force vs Time graphs
  • Basic knowledge of area calculation in physics
  • Ability to interpret graphical data
NEXT STEPS
  • Study the relationship between impulse and momentum in physics
  • Learn how to calculate area under curves in various types of graphs
  • Explore different types of Force vs Time graphs and their implications
  • Investigate the concept of time-averaged force in more complex scenarios
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Students studying physics, educators teaching mechanics, and professionals analyzing dynamic systems involving force and momentum.

haroldham
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This is really simple, but I can not remember how to find the average force in a Force vs TIme graph.
 
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Think about the height of a "[certain] rectangle." Think area.
 
robphy said:
Think about the height of a "[certain] rectangle." Think area.
Ok, you completely lost me, but I think I figured it out. This certain graph increases, remains constant, then decreases. Do I take the final force of each section, add it to the initial force of each section, divide that value by the time of that section, then average those together?
 
Presumably, you mean "time-averaged force".
The area under your graph is equal to the impulse (ie, the change in momentum).
The "time-averaged force" you seek is the constant force you would apply in the same amount of time in order to obtain the same change in momentum. Translate the last sentence into facts about the graph.
 
Oh, ok I get it. It is impulse divided by time.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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