Im doing Physics 12 with equilibrium
The diagram shows a beam 3.2 m long with masses hanging from it. The mass of the beam is negligible in comparison with the other masses.
a.) If the beam is in equilibrium, what is the force of tension in the cable?
b.) If the beam is in equilibrium with the 150kg mass 3.2 m from the 90 kg mass, how far is the 90kg mass from the cable?
c.) If the force of tension in the cable is 2352 N and the cable is attached 2.2 m from the right end of the beam, what is the net torque on the beam about the right end?
d.) If the force of tension in the cable is 2352 N and the cable is attached 2.2 m from the right end of the beam, what is the torque about the point where the cable is attached to the beam?
Net Torque = 0
Net Fx = 0
Net Fy = 0
Torque = Force x length
Torque = mass x gravity x length
The Attempt at a Solution
There were many similar examples but not in this design. So im unsure if im doing it right.
If you could at least answer question part a
I would greatly appreciate it