How do I find f'(1) using implicit differentiation?

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Discussion Overview

The discussion revolves around finding the derivative f'(1) using implicit differentiation, based on the equation x^3 * f(x) + (f(x))^3 + f(x^3) = 3, with the condition that f(1) = 2. Participants seek clarification and assistance with the implicit differentiation process as part of an exam review.

Discussion Character

  • Exploratory
  • Technical explanation
  • Homework-related

Main Points Raised

  • One participant presents the implicit differentiation problem and expresses uncertainty about how to proceed.
  • Another participant clarifies the equation format and restates the problem correctly.
  • A third participant provides a step-by-step approach to applying implicit differentiation, suggesting to set x=1 and solve for f'(1).
  • An unrelated post introduces a different derivative problem, which is met with criticism for diverting from the original topic.
  • Responses to the unrelated post include a request to start a new thread and confusion regarding the notation used.

Areas of Agreement / Disagreement

Participants generally agree on the need to use implicit differentiation to find f'(1), but the discussion remains focused on the original problem without reaching a consensus on the final steps or solutions. The unrelated post introduces disagreement regarding thread etiquette and clarity of notation.

Contextual Notes

The discussion does not resolve the mathematical steps necessary to find f'(1), and there are limitations in the clarity of notation presented in the unrelated post.

SSUP21
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"implicit differentiation"

if [x][3] * f(x) + [(f(x))][3] + f([x][3]) = 3 and f(1)= 2 find f'(1)

NEED HELP REVIEW QUESTION FROM EXAM REVIEW
DONT KNOW WHAT TO DO
 
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x^3 * f(x) + (f(x))^3 + f(x^3) = 3
and f(1) = 2 find f'(1)

formating error in original post
 


Use "implicit differentiation": (x^3 f(x)+ (f(x))^3+ f(x^3))'= 3x^2f(x)+ x^3 f'(x)+ 3f(x)^2 f'(x)+ f'(x^3)(3x^2)= 0. Set x= 1 and solve for f'(1).
 


i have a derivative problem that reads 4/ ^5sqrt(x^5). I am not sure how to work the problem out.
 


1. Please don't hijack other peoples threads for new questions- start your own thread.
2. I have no idea what "4/ ^5" is supposed to mean.
3. sqrt(x^5)= x5/4.
 

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