How do I find the derivatives of f and g?

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The discussion focuses on finding the derivatives of the parametric equations x = f(t), y = g(t), z = t, where the curve of intersection of the surfaces defined by the equations x^6 + y^4 + z^7 - 3xyz = 0 and xy + yz + zx - 3z^4 = 0 is analyzed near the point (1,1,1). To determine the derivatives f'(t) and g'(t), implicit differentiation of the given equations is necessary. Additionally, the tangent line to the curve at the point (1,1,1) can be derived using the calculated derivatives.

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given that near (1,1,1) the curve of intersection of the surfaces:
x^6 + y^4 + z^7 -3xyz = 0 and
xy + yz + zx - 3z^4 = 0
has the paramteric equations x = f(t), y = g(t), z = t with f and g differentiable, how do i find rhe derivatives of f and g?
and the tangent line to the curve of intersection at (1,1,1)?
 
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ice_cream_cone said:
given that near (1,1,1) the curve of intersection of the surfaces:
x^6 + y^4 + z^7 -3xyz = 0 and
xy + yz + zx - 3z^4 = 0
has the paramteric equations x = f(t), y = g(t), z = t with f and g differentiable, how do i find rhe derivatives of f and g?
and the tangent line to the curve of intersection at (1,1,1)?
[tex]\vec{\mathbf{r}}=f(t)\,\hat{\mathbf{i}}+g(t)\,\hat{\mathbf{j}}+t\,\hat{\mathbf{k}}[/tex]

What would happen if you plugged these values of x, y, and z into the original two equations?
 
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