MHB How do I find the Laplace Transform for U3(t)(t-3)^5/2?

ineedhelpnow
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I'm working on a few problems to find Laplace transforms and I got stuck on this one.
${U}_{3}(t){(t-3)}^{5/2}$

It looks different from the other I've been doing so I don't really know how to get started
 
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According to a table I have, if we are given:

$$f(t)=g(t)u(t-a)$$ where $0\le a$

then:

$$F(s)=e^{-as}\mathcal{L}\{g(t+a)\}(s)$$

Does this help?
 
thank you :) i didn't notice anything of that form in my table
 
So I tried to work on this problem but I can't seem to figure it out. I just have no idea what I'm doing with it.
 
nervmind! got it
 
I have the equation ##F^x=m\frac {d}{dt}(\gamma v^x)##, where ##\gamma## is the Lorentz factor, and ##x## is a superscript, not an exponent. In my textbook the solution is given as ##\frac {F^x}{m}t=\frac {v^x}{\sqrt {1-v^{x^2}/c^2}}##. What bothers me is, when I separate the variables I get ##\frac {F^x}{m}dt=d(\gamma v^x)##. Can I simply consider ##d(\gamma v^x)## the variable of integration without any further considerations? Can I simply make the substitution ##\gamma v^x = u## and then...

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