How do i know what a function describe a wave?

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The discussion focuses on determining whether the functions y(x,t) = x² + v²t² and g(x,t) = 2Acos(kx)cos(wt) satisfy the differential equation for a one-dimensional wave. The derivatives of these functions are calculated, showing that d²y/dt² = 2v² and d²y/dx² = 2, while for g(x,t), d²g/dt² = -2Aw²cos(kx)cos(wt) and d²g/dx² = -2Ak²cos(kx)cos(wt). The comparison indicates that both functions can be classified as wave functions if they meet the wave equation criteria. It is confirmed that a constant wave can indeed be expressed as a function of x - vt. Therefore, the functions are valid representations of waves.
Darly
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Homework Statement


Show that the funtions y(x,t) and g(x,t) satisfy the differential equation of a wave unimensional. What function is a wave?

Homework Equations


y(x,t)=x² +v²t² ; d(x,t)= 2Acos(kx)cos(wt)

frac{d²y}{dt²}=2v²

frac{d²y}{dx²}=2

The Attempt at a Solution



frac{d²y}{dt²}=2v²

frac{d²y}{dx²}=2

frac{d²g}{dt²}= -2Aw²cos(kx)cos(wt)
frac{d²g}{dx²}= -2Ak²cos(kx)cos(wt)

Comparing the two functions with the wave equations with y(x,t) and g(x,t) satisfy the equation differential of wave, if all is correct, can i say that the functions are waves. ?
 
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Darly said:
if all is correct, can i say that the functions are waves. ?
Yes.
 
A constant wave can be written as a function of x-vt.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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