orla22 Messages 22 Reaction score 0 Thread starter Apr 13, 2009 #1 How do i open circuit phase R. Line number 4 on the digram being phase R? Attachments CIRC.jpg 50.1 KB · Views: 496
Astronuc Staff Emeritus Science Advisor Gold Member 2025 Award Messages 22,657 Reaction score 7,733 Apr 13, 2009 #2 I'm not sure what you mean by 'How do i open circuit phase R'. If the impedance (resistor) in line 4 breaks or burns out it is open. I suspect this is a question about an unbalanced Y.
I'm not sure what you mean by 'How do i open circuit phase R'. If the impedance (resistor) in line 4 breaks or burns out it is open. I suspect this is a question about an unbalanced Y.
orla22 Messages 22 Reaction score 0 Apr 13, 2009 #3 ok so i should open circuit it by removing the load in line 4 correct and draw a direct line to the source?
ok so i should open circuit it by removing the load in line 4 correct and draw a direct line to the source?
Astronuc Staff Emeritus Science Advisor Gold Member 2025 Award Messages 22,657 Reaction score 7,733 Apr 13, 2009 #4 An open circuit means the conduction has failed, i.e. it is broken. If one wants to model an open ciruit, one would have to add a switch, which then opens. For example _______________ is closed _________/ _____ is open
An open circuit means the conduction has failed, i.e. it is broken. If one wants to model an open ciruit, one would have to add a switch, which then opens. For example _______________ is closed _________/ _____ is open